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7nadin3 [17]
3 years ago
15

A construction worker puts 20J of energy in to one strike of his hammer on the head of a nail. The energy transferred to driving

d nail in to d wood is 8J. What is d efficiency of d construction worker's hammering?​
Physics
2 answers:
KengaRu [80]3 years ago
4 0

Answer:

The efficiency can be found using the formula ;

efficiency=energy output divided by energy input ×100%.

efficiency=8.0j÷ 20j × 100%

efficiency=0.4 ×100%

efficiency=40%.

the efficiency of the hammer strike was 40%. vibration and heating of the nail are two possible reasons for the energy loss.

Slav-nsk [51]3 years ago
3 0

Answer:

efficiancy=40 percent

Explanation:

efficiency=energy output/energy input×100

efficiancy=8J/20J×100

efficiancy=0.4×100

efficiancy=40 percent

Mark brianliest if my answer suit your question..

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Sever21 [200]
Refer to the diagram shown below.

Define the unit vector i to point in the eastern direction, and the unit vector j to point in the northern direction.

The first distance is 184 m west. It is represented by
d₁ = -184 i

The second distance is 220 m at 30° south of east. It is
d₂ = 220(cos 30° i - sin 30° j) = 190.53 i - 110 j

The third distance is 104 m at 80 east of north. It is
d₃ = 104(sin 80° i + cos 80° j) =  102.42 i + 18.06 j

Let the fourth distance be 
d₄ = a i + b j

Because the traveler ends back at the original position, the vector sum of the distances is zero. It means that each component of the vector sum is zero.

The x-component yields
-184 + 190.53 + 102.42 + a = 0
a = -108.95

The y-component yields
0 - 110 + 18.06 + b = 0
b = 91.94

The magnitude of the fourth displacement is
√[(-108.95)² + 91.94² ] = 142.56 m

The direction is at an angle θ north of west, given by
θ = tan⁻¹ (91.94/108.95) = 40.2°

Answer:
The fourth displacement has a magnitude of 142.56 m. It is about 40° north of west.

7 0
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Answer:200 m

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