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kirill115 [55]
3 years ago
15

What do all properties of matter have in common

Chemistry
2 answers:
VashaNatasha [74]3 years ago
8 0
No because some properties of matter are different from others
Wewaii [24]3 years ago
7 0

Answer:

they all matter

Explanation:

cause you matter :)

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Please answer number 2
alexandr402 [8]

Answer:

A

Explanation:

Because Rainwater can get acidic because of the carbonic acid that it contains

8 0
3 years ago
I want to write the answer down so please answer it step by step
olga55 [171]
I suck at chemistry but i have a friend that can help
6 0
3 years ago
If a reaction ends with 5.5 grams of products, how many grams of reactants were required to start the reaction?
xz_007 [3.2K]
5.5 grams of reactants. According to the Law of Conservation of Mass, mass isn’t created or lost through any chemical changes, so the total mass should remain constant from the initial reactants to the final products.
5 0
3 years ago
Butane (C4 H10(g), mc031-1.jpgHf = –125.6 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , mc031-2.jpgHf = –393.5 kJ/
ankoles [38]

The balanced chemical equation for the combustion of butane is:

2C_{4}H_{10}(g) +13 O_{2}(g)-->8CO_{2}(g)+10H_{2}O(g)

ΔH_{reaction}^{0} = Σn_{products}ΔH_{f}^{0}_{(products)}-Σn_{reactants}ΔH_{f}^{0}_{(reactants)}

                         = [{8*(-393.5kJ/mol)}+{10*(-241.82kJ/mol)}]-[{2*(-125.6kJ/mol)}+13*(0 kJ/mol)}]=[-3148kJ/mol+(-2418.2kJ/mol)]-[(-251.2kJ/mol)+0]

                      = -5315 kJ/mol

Calculating the enthalpy of combustion per mole of butane:

1mol C_{4}H_{10}*( \frac{-5315kJ}{2mol C_{4}H_{10} })=-2657.5 \frac{kJ}{molC_{4}H_{10}}

Therefore the heat of combustion per one mole butane is -2657.5 kJ/mol

Correct answer: -2657.5 kJ/mol

6 0
3 years ago
What is a inference that you see by just holding a Tarantula in your hand
4vir4ik [10]
That you hate spiders and that the thing is way to large?
4 0
3 years ago
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