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dybincka [34]
3 years ago
13

A certain alkyl halide is reacted with OH- to form an alcohol. The alkyl halide is optically active but the product(s) is/are op

tically inactive. Which of the following could be the reactant?a) 3-bromo-3-methylhexane.b) 1-chlorobutane.c) 2-bromo-2-methylbutane.d) 3-bromo-2,3,4-trimethypentane.
Chemistry
1 answer:
Snowcat [4.5K]3 years ago
8 0

Answer:

a. 3-brumo - 3-methylhexane

Explanation:

Alkyl Halides can undergo substitution reactions. Nucleophiles are electron rich species and has negative charge while Electrophiles are electron deficient species which carry positive charge. Alkyl halide which have polar carbon atom are electrophiles.

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What did electrons from the ionized air do to the oil drops?
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Answer:

The famous oil drop experiment exploits that fact that an oil drop in an electronic field will get negative charge accumulation which can be balanced and observed in order to determine the charge of an electron.
6 0
2 years ago
Read 2 more answers
Be sure to answer all parts. Nitric oxide (NO) reacts with oxygen gas to form nitrogen dioxide (NO2), a dark brown gas: 2NO(g) +
notka56 [123]

<u>Answer:</u> NO is the limiting reagent in the given reaction and 0.857 moles of NO_2 will be produced.

<u>Explanation:</u>

Limiting reagent is defined as the reagent which is present in less amount and it limits the formation of products.

Excess reagent is defined as the reagent which is present in large amount.

For the given chemical reaction:

2NO(g)+O_2(g)\rightarrow 2NO_2(g)

We are given:

Moles of NO = 0.857 mol

Moles of oxygen = 0.498 mol

By stoichiometry of the reaction:

If 2 moles of NO reacts with 1 mole of oxygen gas.

So, 0.857 moles of NO will react with = \frac{1}{2}\times 0.857=0.4285mol of O_2

As, the given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, NO is considered as the limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

If 2 moles of NO produces 2 moles of nitrogen dioxide gas.

So, 0.857 moles of NO will produce = \frac{2}{2}\times 0.857=0.857mol of NO_2

Hence, NO is the limiting reagent in the given reaction and 0.857 moles of NO_2 will be produced.

6 0
3 years ago
Which statement is true of the motion of the ball?
Pepsi [2]
Your answer would be answer choice D. The ball is accelerating as the velocity is increasing at a constant rate.

Hope this helps,
♥<em /><em>A.W.E.<u>S.W.A.N.</u></em>♥

3 0
3 years ago
When an aqueous solution of silver nitrate is
Andre45 [30]

Answer:

K^{+} and NO_{3}^{-}

Explanation:

The equation for the reaction is AgNO3(aq) + KCl(aq) ==> AgCl(s) + KNO3(aq)

With all the ions, it is

Ag^{+}(aq) + NO_{3} ^{-}(aq) + K^{+}(aq) + Cl^{-}(aq)  ==> AgCl(s) +

K^{+} and NO_{3} ^{-} do not change, so they are the spectator ions and are removed

The ionic equation is:

Ag^{+}(aq) + Cl^{-}(aq) ==> AgCl(s)

8 0
2 years ago
What mass of zinc (molar mass 65.4 g moll) does it take to produce 0.50 mole of H2(g)?
Hatshy [7]

Answer:

32.7 g of Zn

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Zn + 2HCl —> ZnCl₂ + H₂

From the balanced equation above,

1 mole of Zn reacted to produce 1 mole of H₂

Next, we shall determine the number of mole of Zn required to produce 0.5 mole of H₂. This can be obtained as follow:

From the balanced equation above,

1 mole of Zn reacted to produce 1 mole of H₂.

Therefore, 0.5 mole of Zn will also react to produce to 0.5 mole of H₂.

Thus, 0.5 mole of Zn is required.

Finally, we shall determine the mass of 0.5 mole of Zn. This can be obtained as follow:

Mole of Zn = 0.5 mole

Molar mass of Zn = 65.4 g/mol

Mass of Zn =?

Mass = mole × molar mass

Mass of Zn = 0.5 × 65.4

Mass of Zn = 32.7 g

Thus, 32.7 g of Zn is required to produce 0.5 mole of H₂.

4 0
2 years ago
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