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givi [52]
3 years ago
9

Explain the difference, with sketches, between the titration curves of monoprotic acid and a triprotic acid.

Chemistry
1 answer:
kvasek [131]3 years ago
6 0

Answer:

A monoprotic acid has only one equivalence point in a titration curve while a triprotic acid has three equivalence points.

Explanation:

Monoprotic acids, HA, are acids that are able to donate one proton per molecule during the process of ionization or dissociation as shown below:

HA ----> H⁺ + A⁻

A triprotic acid is a polyproprotic acid, that is acids that can donate more than one proton per molecule during ionization. a triprotic acid can donate three protons per molecule during the process of ionization. The dissociation of a triprotic acid is shown below;

H₃A -----> H₂A⁻ + H⁺

H₂A⁻ ----> HA²⁻ + H⁺

HA²⁻ -----> A³⁻ + H⁺

The value Ka, is known as the acid dissociation constant. It is found by looking at the equilibrium constant for the dissociation of the acid. The higher the Ka, the more the acid dissociates

A titration curve is the plot of the pH of the analyte solution versus the volume of the titrant added as the titration progresses.

In a titration curve in which base is added to acid, the pH rises slowly until the equivalent point at which point the pH remains constant before it begins to rise again on the addition of more base.

In a titration curve of a monoprotic acid, there is only one region in which the equivalence point is obtained corresponding to the point of acid of dissociation of all its protons.

In the titration curve of a triproprotic acid, three equivalent points are obtained corresponding to the point of dissociation of each of three protons of the triprotic acid.

The titration curves are shown below

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Answer;

= g/cm^3

Explanation;

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3 years ago
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erastova [34]

The wavelength of a wave refers to the horizontal distance that is travelled by a wave.

<h3>What is wavelength?</h3>

The wavelength of a wave is given by the formula;

v =λf

f = v/λ

Substituting the values;

f = 3 * 10^8 m/s/410 * 10^-9 m

f = 7.3 * 10^14 Hz

for 2

f = 3 * 10^8 m/s/434 * 10^-9 m

f = 6.9  * 10^14 Hz

for 3

f = 3 * 10^8 m/s/486 * 10^-9 m

f = 6.2  * 10^14 Hz

for 4

f = 3 * 10^8 m/s/657 * 10^-9 m

f = 4.6 * 10^14 Hz

Learn more about wavelength:brainly.com/question/13533093

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4 0
1 year ago
a certain skin lotion is a fine mixture of water and various oils. this lotion is cloudy and cannot be separated into oil and wa
PolarNik [594]

Answer: The skin lotion is a colloidal mixture of water and various oils.

Explanation:

Mixture: Blend of of two or more components which are chemically unreactive to give any product.

Mixture are defined as  of three types:

Solutions : Mixture in which one component is completely distributed in an other component resulting in clear mixture. They cannot be separated into its components on standing or by filtration.

Suspensions: Mixture in which one component is not completely or uniformly distributed in another component.They separate out into layers when kept undisturbed.

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A skin lotion is a fine mixture of water and oils. it is a cloudy mixture and cannot be separated with help of filtration. Also its components also not separates out on standing. All these properties shown by skin lotion is of colloidal mixture.


3 0
3 years ago
An equal number of moles of KI (potassium iodide) and MgI2 (magnesium iodide) are dissolved in equal volumes of water.
SOVA2 [1]
<span>  As we know that MgI2 (magnesium iodide) when dissociated it gives more ions than  the KI so it has more boiling point as its boiling point is high it means that it boils more so it has low vapor pressure and freezing point

On the other hand as we know that KI dissociates into two  ions so so it has high freezing and vapor pressure
hope it helps</span>
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3 years ago
Standard reduction potentials for nickel(II) and copper(II) The standard reduction potential for a substance indicates how readi
AleksandrR [38]

Answer:

The standard potential, E cell, for this galvanic cell is 0.5670V

Explanation:

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Cu²⁺(aq) +  2e-    →  Cu(s)          E red = + 0.337V    CATHODE

ΔE° = E cathode - E anode

ΔE° = 0.337V - (0.23V) = 0.5670 V

6 0
3 years ago
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