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3 years ago

How many molecules are found in 60 grams of KOH? Explain step by step please

Chemistry

1 answer:

densk [106]3 years ago

6 0

Answer:

6.624× 10²³ molecules

Explanation:

Given data:

Mass of KOH = 60 g

Number of molecules = ?

Solution:

First of all we will calculate the number of moles.

Number of moles = mass/molar mass

Number of moles = 60 g/ 56.1 g/mol

Number of moles = 1.1 mol

Now number of molecules are determine by using Avogadro number.

1 mole = 6.022 × 10²³ molecules

1.1 mol × 6.022 × 10²³ molecules / 1mol

6.624× 10²³ molecules

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

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Leto [7]

Answer:

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Explanation:

First calculate the amount of moles.

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Then you can calculate the molarity by dividing the moles with the volume so 2.13 mol / 1.5 l = 1.42 M

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2 years ago

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Answer:

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3 years ago

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3 years ago

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4 years ago

Which of the following has no electrons? Use a periodic table. Question 1 options: H He H– He 2+ Save

Elodia [21]

An electron is a negatively charged subatomic particle present in the space outside the nucleus of an atom. The loss of electron from an atom results in the formation of cation whereas gaining of electron by an atom results in the formation of anion. The cation possesses positive charge due to loss of electron and anion possesses negative charge due to gain of electron.

The neutral atom has no charge on it.

For given atomic symbols:

The atomic number of hydrogen is 1 and the given symbol has no charge that means it is in its neutral state. So, the number of electrons in $H$ is 1.

$He$

The atomic number of helium is 2 and the given symbol has no charge that means it is in its neutral state. So, the number of electrons in $He$ is 2.

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4 years ago