Question

In the first 21.0 s of this reaction, the concentration of HBr dropped from 0.550 M to 0.506 M . Calculate the average rate of the reaction in this time interval.

Answer 1

Answer:

1.048x10⁻³M/s is the rate of reaction

Explanation:

Based on the reaction:

2HBr → H₂ + Br₂

The rate of reaction is defined as:

1/2 Δ[HBr] / Δt

1/2 because the reaction is consuming 2 times HBr per mole of reaction

Where Δ[HBr] is 0.550M - 0.506M = 0.044M

And Δt is 21.0s. The average rate of reaction is:

1/2 0.044M / 21.0s =

1.048x10⁻³M/s is the rate of reaction