First off, the chemical equation needs to be balanced. Since there are 2 oxygen atoms in the reactants, we must produce 2 moles of MgO, which means we need 2 moles of Mg, giving:
2Mg + O2 --> 2MgO
Therefore for a stoichiometric reaction where no reactant is left over, the number of moles of magnesium must be double that of oxygen. However, as seen, the molar ratio of magnesium to oxygen is 2:5, meaning oxygen is in large excess, and Magnesium is the limiting reactant. Therefore the answer is A.
Answer:
Na₂O is the formula for the ionic compound "sodium oxide".
It has 2 sodium atoms and 1 oxygen atom.
The number of atoms for an element are written as a subscript after the element. "1" subscripts are not written.
The names of the elements are found on the periodic table.
Answer:
(Léase explicación)
Explanation:
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Hello!
We have the following data:
v (volume) = ? (in L)
n (number of mols) = 1,5 mol
T (temperature) = 22 ºC
First let's convert the temperature on the Kelvin scale, let's see:
TK = TºC + 273,15
TK = 22 + 273,15
TK = 295,15
P (pressure) = 100 kPa → P = 100000 Pa → P ≈ 0,987 atm
R (gas constant) = 0,082 atm.L / mol.K
<span>We apply the data above to the Clapeyron equation (gas equation), let's see:
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I hope this helps. =)
Answer:
one of the atoms sharing electrons is more electronegative than the other atom
Explanation: