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Radda [10]
3 years ago
8

Is there any one who can help me in chemistry?

Chemistry
1 answer:
BaLLatris [955]3 years ago
4 0
I can try.
Whats the question
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TIMED HELP ASAP
anastassius [24]

Answer:

TIMED HELP ASAP

19.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the dissolution of MgSO₄. (The specific heat of water is 4.184 J/g・°C and the density of the water is 1.00 g/mL). You can assume that the specific heat of the solution is the same as that of water.

7 0
3 years ago
State two things you notice about a metal when being touched
vivado [14]

Answer: one thing you may notice when you touch metal is a small electric shock, and depending on the temperature, it could be hot, or cold.

4 0
3 years ago
8. 53.4 mL of a 1.50 M solution of NaCl is on hand, but you need some 0.800 M
bulgar [2K]
8. 100.13 ml
9. 75 ml
10. 1066.7 ml, hope that's help
6 0
3 years ago
Which of the following is a mixture?
KATRIN_1 [288]
C is a mixture!!!!!!!!!!!!!

7 0
4 years ago
Which of the following represents the least number of molecues?
Mars2501 [29]

Answer:

Answer: a) 20g of H2O (18.02 g/mol) molecules=6.68x10^23

Explanation:

In order to find the amount of molecules of each of the options, we need to follow the following equation.

molecules=\frac{mass(g)x6.022x10^{23}(molecules/mol) }{atomic weight(g/mol)}

So, let´s get the number of molecules for each of the options.

a) molecules=\frac{20(g)x6.022x10^{23}(molecules/mol) }{18.02(g/mol)}=6.68x10^{23}molecules

b) molecules=\frac{77(g)x6.022x10^{23}(molecules/mol) }{16.06(g/mol)}=2.89x10^{24}molecules

c) molecules=\frac{68(g)x6.022x10^{23}(molecules/mol) }{42.09(g/mol)}=9.73x10^{23}molecules

d) molecules=\frac{100(g)x6.022x10^{23}(molecules/mol) }{44.02(g/mol)}=1.37x10^{24}molecules

d) molecules=\frac{84(g)x6.022x10^{23}(molecules/mol) }{20.01(g/mol)}=2.53x10^{24}molecules

the smalest number is in option a)

Best of luck.

7 0
3 years ago
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