The two naturally occurring isotopes of bromine are
1 answer:
Answer:
The decreasing order of masses of for different BrCl molecules :
=
=
Explanation:
The two naturally occurring isotopes of bromine are
81-Br (80.916 amu, 49.31%) 79-Br (78.918 amu, 50.69%).
The two naturally occurring isotopes of chlorine are
37-Cl (36.966 amu, 24.23%) and 35- Cl (34.969 amu, 75.77%).
Molar mass of BrCl molecule composed of 81-Br and 37-Cl.
Mass of 81-Br = 80.916 amu
Mass of 37-Cl = 36.966 amu
Molar mass of this BrCl molecule, = 80.916 amu + 36.966 amu
= 117.882 amu
Molar mass of BrCl molecule composed of 79-Br and 35-Cl.
Mass of 79-Br = 78.918 amu
Mass of 35-Cl = 34.969 amu
Molar mass of this BrCl molecule = 78.918 amu + 34.969 amu
= 113.887 amu
Molar mass of BrCl molecule composed of 81-Br and 35-Cl.
Mass of 81-Br = 80.916 amu
Mass of 35-Cl = 34.969 amu
Molar mass of this BrCl molecule, = 80.916 amu + 34.969 amu
= 115.885 amu
Molar mass of BrCl molecule composed of 79-Br and 37-Cl.
Mass of 79-Br = 78.918 amu
Mass of 37-Cl = 36.966 amu
Molar mass of this BrCl molecule, = 78.918 amu + 36.966 amu
= 115.884 amu
The decreasing order of masses of for different BrCl molecules :
=
=
You might be interested in
Answer:
<u><em>Volume of NaOH, aka V2 = 6.32 mL to 3 sig. fig.</em></u>
A chemistry student weighs out 0.0941 g of hypochlorous acid (HClo) into a 250. ml. volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.2000 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits mL.
Explanation:
1 mole HClO = 74.44g
0.0941g = = 0.00126 moles
Concentration = no. of moles/volume in L
Hence, Concentration of HClO = 0.00126/ 0.250L
= 0.005M.
C1V1 =C2V2
0.005 × 250 mL = 0.2 × V2
<u><em>Volume of NaOH, aka V2 = 6.32 mL to 3 sig. fig.</em></u>