Centripetal force is the force that needs to be exerted on an
object in order to keep it on a circular path with a certain radius.
If the force is there but it isn't strong enough, then the object will
travel in a circular curve alright, but it'll be bigger than the radius
you want. If the force isn't there at all, then the object will move
in a straight line.
To keep a mass ( 'M' ) moving with speed 'S' on a circular path
with radius of 'R', the force on it has to be
Force = M S² / R
and it always has to point from the object toward the center
of the circle.
That formula is pretty simple, but in order to use it just as it
stands, the quantities have to be in SI base units ... meters,
kilograms, and seconds ... so we have to massage the speed,
and change it from km/hr to m/s .
Speed = (90 km/hr) x (1,000 m/km) x (1 hr / 3,600 sec)
= (90 x 1,000 / 3,600) (m / sec) = 25 m/s .
Now we're ready to use the formula.
Centripetal force = (mass) x (speed)² / (radius)
= (2,000 kg) x (25 m/s)² / (80 m)
= (2,000 x 625 / 80) (kg-m / sec²)
= 15,625 newtons .
<span>Distance = Speed x Time, we are going to derived our equation.
You can compute for the average speed using the equation: speed = distance ÷ time.
So plugging in our data, it will look like:
Speed = distance / time
= 100 m / 50 s
= 2 m/sec
Juan average speed is 2 m / sec. </span>
I think it would be thermal energy
Use the concept of beat frequency to find the applicable final freqeuncy for 20Hz beat frequency.
Beat can be defined as 'the interference pattern between two sounds of slightly different frequencies0
The expression for beat frequency is given as
Where,
Final frequency
Initial frequency
The beat frequency for us is 25Hz and the initial frequency is 240Hz, then
Being an absolute value, two values are possible, both in addition and subtraction:
The two possible values are
Here we have to add the two measurements given in the question
The measurement values are given as 1.0090 cm and 0.02 cm.we have to add them on the basis of significant figure rules.
As per the addition rule in terms of significant figures
1-First we have to select the number of significant digits after the decimal point of each quantity.
2-Now we have to remember that during the addition ,the resultant of two quantities will follow the quantity having least number of significant figures after the decimal point.
3-Here we are considering the minimum number of significant figures after the decimal points not the minimum number of significant figures in case of multiplication and division
Now we have to add these two quantities as per the above rule-
1.0090 cm +0.02 cm
=1.0290 cm
Here the result will follow 0.02 which has minimum number of significant figures after the decimal points.
Hence we have to round off the number from 9 of 1.0290
As 9 is greater than 5 ,so he actual result will be 1.03 cm
