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djyliett [7]
3 years ago
11

Can you explain the three main important reason why we use machine​

Physics
2 answers:
Maru [420]3 years ago
8 0

Answer:

HERE IS YOUR ANSWER

Explanation:

1. The machines makes pur life easier.

2. It makes us do our works faster.

3. It does all the works that are harder for us.

Hope it helps you.

balandron [24]3 years ago
7 0

Explanation:  

First of all some do most of the work for us

Second, us humans are quite lazy

Third, it makes it quite easier in life

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An isotropic point source emits light at wavelength 510 nm, at the rate of 170 W. A light detector is positioned 410 m from the
Wewaii [24]

Answer:

\frac{dB}{dt} = 3.03 \times 10^6 T/s

Explanation:

As we know that the power emitted by the source is given as

P = 170 W

now we know that

P = \frac{N}{t} (\frac{hc}{\lambda})

now we know that energy density is given as

u = \frac{B^2}{2\mu_0} + \frac{\epsilon_0 E^2}{2}

now we have

E = B c

u = \frac{B^2}{2\mu_0}

intensity is defined as

I = \frac{P}{A}

now we have

\frac{I}{c} = u = \frac{B^2}{2\mu_0}[/tex]

now we have

\frac{dB}{dt} = \omega B

\frac{dB}{dt} = \frac{2\pi c B}{\lambda}

\frac{dB}{dt} = \frac{2\pi c \sqrt{2\mu_0 I}}{\lambda\sqrt c}

here we have

I = \frac{P}{4\pi r^2}

I = \frac{170}{4\pi (410)^2}

I = 8.05 \times 10^{-5}

now we have

\frac{dB}{dt} = \frac{2\pi\sqrt{2\mu_0 c (8.05 \times 10^{-5})}}{(510 nm)}

\frac{dB}{dt} = 3.03 \times 10^6 T/s

4 0
3 years ago
The specific heat of water is 4.19 x 103 J/kg°C. How much energy will it take to raise the temperature of 0.5 kg of water by 2 d
fredd [130]
Energy required = mass x specific heat x temperature difference
= 0.5 x 4.19x10^3 x 2
= 4190J
5 0
3 years ago
Help!!!!!!!!!!!!!!!!!!
GREYUIT [131]
I think wind is anther answer
5 0
3 years ago
Select the correct arrows. Identify the arrows that show the correct direction of heat transfer.
NeX [460]

Answer:

Explanation:I Did the test and it said this was the right answer so it probally is

7 0
3 years ago
Calculating the acceleration of two people pulling a box with same force and angle.
Dmitriy789 [7]

Here as we can see there we be net horizontal force acting on it

F_x = F_1cos20 + F_2cos20

also we know that

F_1 = F_2 = 80 N

now we will have

F_x = 2(80cos20)

F_x = 150.35 N

now for net force of box we know

F_x - F_f = ma

150.35 - 100 = ma

20a = 50.35

a = 2.52 m/s^2

so acceleration of the box will be 2.52 m/s/s

7 0
3 years ago
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