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Montano1993 [528]
2 years ago
15

Whats the difference between an inner planet and an outer planet

Physics
2 answers:
Kryger [21]2 years ago
8 0
The outer planets<span> are further away, larger and made up mostly of gas. The </span>inner planets<span> (in order of distance from the sun, closest to furthest) are Mercury, Venus, Earth and Mars. After an asteroid belt comes the </span>outer planets<span>, Jupiter, Saturn, Uranus and Neptune.</span>
Dmitry [639]2 years ago
4 0
The main difference between inner and outer planets<span> is that </span>outer planets<span> are larger and are mainly made of gas. The </span>inner planets<span> are Venus, Mercury, Mars and Earth, while the </span>outer planets<span> are considered to be Saturn, Uranus, Neptune and Jupiter.</span>
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two masses are separated by 1 m. suppose the masses are moved so they are 2 m apart how will the gravitational force change
Verdich [7]
The gravitational force would get stronger because the farther the two masses are separated the more gravitational force will be used to pull them together the closer they are the less gravitational pull is used to pull them together
5 0
3 years ago
A particle moves through an xyz coordinate system while a force acts on it. When the particle has the position vector r with arr
Paha777 [63]

Answer:

The question is incomplete, below is the complete question "A particle moves through an xyz coordinate system while a force acts on it. When the particle has the position vector r with arrow = (2.00 m)i hat − (3.00 m)j + (2.00 m)k, the force is F with arrow = Fxi hat + (7.00 N)j − (5.00 N)k and the corresponding torque about the origin is vector tau = (4 N · m)i hat + (10 N · m)j + (11N · m)k.

Determine Fx."

F_{x}=-1N.m

Explanation:

We asked to determine the "x" component of the applied force. To do this, we need to write out the expression for the torque in the in vector representation.

torque=cross product of force and position . mathematically this can be express as

T=r*F

Where

F=F_{x}i+(7N)j-(5N)k  and the position vector

r=(2m)i-(3m)j+(2m)k

using the determinant method to expand the cross product in order to determine the torque we have

\left[\begin{array}{ccc}i&j&k\\2&-3&2\\ F_{x} &7&-5\end{array}\right]\\\\

by expanding we arrive at

T=(18-14)i-(-12-2F_{x})j+(12+3F_{x})k\\T=4i-(-12-2F_{x})j+(12+3F_{x})k\\\\

since we have determine the vector value of the toque, we now compare with the torque value given in the question

(4Nm)i+(10Nm)j+(11Nm)k=4i-(-12-2F_{x})j+(12+3F_{x})k\\

if we directly compare the j coordinate we have

10=-(-12-2F_{x})\\10=12+2F_{x}\\ 10-12=2F_{x}\\ F_{x}=-1N.m

8 0
3 years ago
A rocket powered sled accelerates a jet pilot in training straight forward from rest to 270 km/h in 12.1 seconds. Find:
Ilia_Sergeevich [38]

Answer:

  1. 6.198 m/s²
  2. 4.48 s
  3. 453.77 m

Explanation:

5 0
2 years ago
How far would a jet going 155 m/s travel in 9 s?
docker41 [41]

Answer:

1,395 m

Explanation:

155×9

multiply m/s by 9s

5 0
3 years ago
A young man walks daily through a gridded city section to visit his girlfriend, who lives m blocks East and nblocks North of whe
Arada [10]

Answer:

The man ate eggs.

Explanation:

He should brush his teeth before seeing his girlfriend.

4 0
2 years ago
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