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Anni [7]
3 years ago
5

Suppose you apply a force of 40 N to a 0.25​-meter-long wrench attached to a bolt in a direction perpendicular to the bolt. Dete

rmine the magnitude of the torque when the force is applied at an angle of 135degrees to the wrench.
Physics
1 answer:
andrezito [222]3 years ago
8 0

Answer:

Torque = 7.07 N.m

Explanation:

It is given that,

Force acting on the wrench, F = 40 N

Length of wrench, l = 0.25 meters

It is attached perpendicular to the bolt such that the force is applied at an angle of 135 degrees to the wrench. The formula for torque is given by :

\tau=r\times F

\tau=rF\ sin\theta

\tau=0.25\ m\times 40\ N\ sin(135)

\tau=7.07\ N.m

So, the magnitude of torque applied to the wrench is 7.07 N-m. Hence, this is the required solution.

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