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Artist 52 [7]
3 years ago
11

7. A cube sits in the Cartesian coordinate system. Each side of the cubeis 2m. Electric charge is distributed in the cube with a

density functionV=xy2e2z(C=m3). Find the total charge in the cube
Physics
1 answer:
Zanzabum3 years ago
4 0

Answer:

Net charge inside the cube is 321.6 C

Explanation:

Given charge density function is ρ = xy^2 e^{2z}

side of cube is 2m

According to the definition of volume charge density total charge is given by

q = total charge = \int {\rho} \, dv where dv = dxdydz is the volume element

on substututing the respected values we get

q = \int\limits^2_0 {x} \, dx \int\limits^2_0 {y^2} \, dy \int\limits^2_0 {e^2^z} \, dz  

on solving the above integration we get

q =  \frac{x^2}{2} x \frac{y^3}{3} x \frac{e^2^z}{2}

⇒ q = 321.6 C

Therefore net charge inside the cube is 321.6 C

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       \Delta y  = y_{f} - y_{o} = v_{o} * t + \frac{1}{2}  * g *t^{2}  (2)

  • if we take the river level as our x-axis, this means that yf = 1.3 m and

       y₀ = 20.8 m.

  • At the same time, due to in the vertical direction the car has no initial velocity, this means that  v₀ = 0.
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       t = \sqrt{\frac{2* \Delta y}{g} } = \sqrt{\frac{2*19.5m}{9.8m/s2} }  = 2 s  (3)

  • If we choose t₀ =0 ⇒ Δt = t = 2 s
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B)

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       v = \sqrt{v_{x}^{2} + v_{fy}^{2} } } = \sqrt{(26.5m/s)^{2} + (-19.6m/s)^{2}}  = 33.0 m/s  (6)

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