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goldfiish [28.3K]
3 years ago
8

Using the two cell reduction potentials shown for their corresponding reaction, calculate the cell potential for a voltaic cell

made from these two systems. Question 16 options: A) 1.68 V B) –1.68 V C) –0.78 V D) 0.78 V
Chemistry
1 answer:
guajiro [1.7K]3 years ago
6 0

Answer:

The right alternative is Option D (0.78 V).

Explanation:

According to the question,

The cell potential will be:

= E^0_{Cr_2 O_7/er^{3+}}- E^0_{Fe^{2+}/Fe}

By putting the values, we get

= 1.23-0.45

= 0.78 \ V

Thus the above is the correct option.

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Given the following thermodynamic data, calculate the lattice energy of LiCl:
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Answer:

\boxed{\text{-862 kJ/mol}}

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One way to calculate the lattice energy is to use Hess's Law.

The lattice energy U is the energy released when the gaseous ions combine to form a solid ionic crystal:

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(1)  Li(s) + ½Cl₂ (g) ⟶ LiCl(s);      ΔHf°     = -409 kJ·mol⁻¹

(2) Li(s) ⟶ Li(g);                          ΔHsub =    161 kJ·mol⁻¹

(3) Cl₂(g) ⟶ 2Cl(g)                     BE        =   243 kJ·mol⁻¹

(4) Li(g) ⟶Li⁺(g) +e⁻                   IE₁         =   520 kJ·mol⁻¹

(5) Cl(g) + e⁻ ⟶ Cl⁻(g)                EA₁       =  -349 kJ·mol⁻¹

Now, we put these equations together to get the lattice energy.

                                                <u>E/kJ </u> 

(5) Li⁺(g) +e⁻ ⟶ Li(g)                520

(6) Li(g) ⟶ Li(s)                         -161

(7) Li(s) + ½Cl₂(g) ⟶ LiCl(s)     -409

(8) Cl(g) ⟶ ½Cl₂(g)                   -121.5

(9) Cl⁻(g) ⟶ Cl(g) + e⁻               <u>+349</u>

      Li⁺(g) +  Cl⁻(g) ⟶ LiCl(s)     -862

The lattice energy of LiCl is \boxed{\textbf{-862 kJ/mol}}.

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