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goldfiish [28.3K]
2 years ago
8

Using the two cell reduction potentials shown for their corresponding reaction, calculate the cell potential for a voltaic cell

made from these two systems. Question 16 options: A) 1.68 V B) –1.68 V C) –0.78 V D) 0.78 V
Chemistry
1 answer:
guajiro [1.7K]2 years ago
6 0

Answer:

The right alternative is Option D (0.78 V).

Explanation:

According to the question,

The cell potential will be:

= E^0_{Cr_2 O_7/er^{3+}}- E^0_{Fe^{2+}/Fe}

By putting the values, we get

= 1.23-0.45

= 0.78 \ V

Thus the above is the correct option.

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3d orbital is completely filled.

Explanation:

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6 0
3 years ago
8. A 220 mL sample of helium gas is in a cylinder with a movable piston at 105 kPa and 275K. The piston
Harrizon [31]

The sample has a new pressure of 274kPa. If at 105 kPa and 275K, a 220 mL sample of helium gas is contained in a cylinder with a moving piston. The sample is pushed till it has a 95.0 mL volume and 310K .

The macroscopic characteristics of ideal gases are related by the ideal gas law (PV = nRT). A gas is considered to be perfect if its particles (a) do not interact with one another and (b) occupy no space (have no volume). Where P= pressure  V= volume and T = temperature.

From ideal gas equation

P₁V₁/T₁ =P₂V₂/T₂

105×220÷275 = P₂ ×95÷310

P₂= (105×220×310)÷(275×95)

P2= 7161000/26125

P2 = 274.105 kPa

Hence, the new pressure of helium gas is 274kPa

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8 0
1 year ago
Hace cuanto el hombre estudia el universo
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Answer:

El Big Bang fue el momento, hace 13.800 millones de años, cuando el universo comenzó como una pequeña y densa bola de fuego que explotó. La mayoría de los astrónomos utilizan la teoría del Big Bang para explicar cómo comenzó el universo.

Explanation:

3 0
3 years ago
What is the concentration of a potassium iodate solution after you complete the following porcedure? Pipette 10 mL of a 0.31 M p
zubka84 [21]

<u>Given:</u>

Initial concentration of potassium iodate (KIO3) M1 = 0.31 M

Initial volume of KIO3 (stock solution) V1 = 10 ml

Final volume of KIO3 V2 = 100 ml

<u>To determine:</u>

The final concentration of KIO3 i.e. M2

<u>Explanation:</u>

Use the relation-

M1V1 = M2V2

M2 = M1V1/V2 = 0.31 M * 10 ml/100 ml = 0.031 M

Ans: The concentration of KIO3 after dilution is 0.031 M

4 0
2 years ago
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