<span>c. The molecules are closer together as a gas than they do as a liquid.</span>
Answer:
H₂SO₄
Explanation:
We have a compound formed by 0.475 g H, 7.557 g S, 15.107 g O. In order to determine the empirical formula, we have to follow a series of steps.
Step 1: Calculate the total mass of the compound
Total mass = mass H + mass S + mass O = 0.475 g + 7.557 g + 15.107 g
Total mass = 23.139 g
Step 2: Determine the percent composition.
H: (0.475g/23.139g) × 100% = 2.05%
S: (7.557g/23.139g) × 100% = 32.66%
O: (15.107g/23.139g) × 100% = 65.29%
Step 3: Divide each percentage by the atomic mass of the element
H: 2.05/1.01 = 2.03
S: 32.66/32.07 = 1.018
O: 65.29/16.00 = 4.081
Step 4: Divide all the numbers by the smallest one
H: 2.03/1.018 ≈ 2
S: 1.018/1.018 = 1
O: 4.081/1.018 ≈ 4
The empirical formula of the compound is H₂SO₄.
Answer:
c
Explanation:
hope it helps ...........
Answer:
Chlorine is more electronegative than iodine. The electronegativity of chlorine is 3.16. The electronegativity of iodine is 2.66.
Answer:
CH₃NH₃⁺ is a weak acid.
HPO₄²⁻ has a negligible acidity.
CH₄ has a negligible acidity.
HNO₂ is a weak acid.
Explanation:
There are 7 strong acids: HCl, HBr, HI, HNO₃, H₂SO₄, HClO₃, HClO₄. The rest of the acids are weak.
CH₃NH₃⁺ is a weak acid, according to the following equation:
CH₃NH₃⁺ ⇄ CH₃NH₂ + H⁺
HPO₄²⁻ can act as an acid or as a base:
<u>Acid reaction:</u> HPO₄²⁻ ⇄ PO₄³⁻ + H⁺
<u>Basic reaction:</u> HPO₄² + H₂O ⇄ H₂PO₄⁻ + OH⁻
Given Kb > Ka, HPO₄²⁻ has a negligible acidity.
CH₄ cannot release nor accept H⁺ so it has a negligible acidity.
HNO₂ is a weak acid, according to the following reaction:
HNO₂ ⇄ H⁺ + NO₂⁻
