Answer:- Chlorine(Cl)
Explanations:- Electron affinity is the amount of energy released when an electron is added to an element in it's gaseous state. Electron affinity increases in a period on going left to right as the size of the element decreases and it's effective nuclear charge increases and this facilitate an element to accept the electron.
The elements mentioned here in the question belongs to the same group and out of these, chlorine is on the right most side and so it is correct choice.
Hence, Chlorine(Cl), because it is a halogen with a high effective nuclear charge is the correct choice.
The volume of air mattress is = 1.127 L
<u><em>calculation</em></u>
The volume of air is calculated using the ideal gas equation
that is Pv=nRT where,
P(pressure)= 3.5 kilopascals convert into Atm
1 atm =0.00987 KPa
?atm = 3.5 Kpa
= (3.5 kpa x 1 atm) / 0.00987 kpa =354.6 atm
V(volume) = ?
n( no of moles) = 16.5 moles
R (gas constant)= 0.0821 L.atm/mol.K
T(Temperature) = 295 K
make V the subject of the formula V=nRT/P
V= ( 16.5 moles x 0.0821 atm/mol.K x 295 k) /354.6 atm =<u><em>1.127 L</em></u>
A. The wavelength of light that is emitted is 122 nm.
<h3>
What is wavelength?</h3>
Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire.
<h3>Wavelength of light is emitted</h3>
When an electron falls from the n = 2 to the n = 1 energy levels in a Hydrogen atom, the wavelength of light is emitted is calculated as follows;
¹/λ = R(1/n₁² - 1/n₂²)
¹/λ = 109677(1/1 - 1/2²)
¹/λ = 109677(1 - ¹/₄)
¹/λ = 82,257.25
λ = 1/8,225.25
λ = 1.22 x 10⁻⁵ cm
λ = 1.22 x 10⁻⁷ m
λ = 122 nm
Thus, the wavelength of light that is emitted is 122 nm.
Learn more about wavelength here: brainly.com/question/10728818
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Answer:
The pH of the solution is 8.
Explanation:
To which options are correct, let us determine the concentration of the hydroxide ion, [OH-] and the pH of the solution. This is illustrated below:
1. The concentration of the hydroxide ion, [OH-] can be obtained as follow:
pOH = –Log [OH-]
pOH = 6
6 = –Log [OH-]
–6 = Log [OH-]
[OH-] = Antilog (–6)
[OH-] = 1x10^–6 mol/L
2. The pH of the solution can be obtained as follow:
pH + pOH = 14
pOH = 6
pH + 6 = 14
pH = 14 – 6
pH = 8.
From the calculations made above,
[OH-] = 1x10^–6 mol/L
pH = 8.
Therefore, the correct answer is:
The pH of the solution is 8
