First we have to find moles of C:
Molar mass of CO2:
12*1+16*2 = 44g/mol
(18.8 g CO2) / (44.00964 g CO2/mol) x (1 mol C/ 1 mol CO2) =0.427 mol C
Molar mass of H2O:
2*1+16 = 18g/mol
As there is 2 moles of H in H2O,
So,
<span>(6.75 g H2O) / (18.01532 g H2O/mol) x (2 mol H / 1 mol H2O) = 0.74mol H </span>
<span>Divide both number of moles by the smaller number of moles: </span>
<span>As Smaaler no moles is 0.427:
So,
Dividing both number os moles by 0.427 :
(0.427 mol C) / 0.427 = 1.000 </span>
<span>(0.74 mol H) / 0.427 = 1.733 </span>
<span>To achieve integer coefficients, multiply by 2, then round to the nearest whole numbers to find the empirical formula:
C = 1 * 2 = 2
H = 1.733 * 2 =3.466
So , the empirical formula is C2H3</span>
Hello!
When something is a liquid then turns to a gas, this is known as evaporating so we would call it the heat of evaporation or also known as latent heat. Just remember liquid to gas is vapor!
I hope this helped!
I am, yours most sincerely,
SuperHelperThingy
I am in fire / ems class does anyone know anything about firefighting please answer this question thanks
What are the five fire department notifications systems chapter 37 fire detection suppression and protection systems
Answer: This is an oxidation-reduction (redox) reaction:
3 C-II - 12 e- → 3 CII (oxidation)
4 CrVI + 12 e- → 4 CrIII (reduction)
C2H5OH is a reducing agent, K2Cr2O7 is an oxidizing agent.
