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labwork [276]
3 years ago
6

Lighting a match changes ch and energy into heat.​

Chemistry
1 answer:
otez555 [7]3 years ago
7 0

Answer:

The answer remains the same. The total amount of energy stays the same because the 1st Law of Thermodynamics states that energy can neither be created nor destroyed, it can only change forms. So the chemical energy is just being converted into heat and light.

Explanation:

hope this helps...

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What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K. The latent heat of vaporization
Arte-miy333 [17]

Answer:

0.89kg

Explanation:

Q=mL L=specific latent heat

Q=energy required in J

m=mass in Kg

Q=mL

m=Q/L

m=2000000J/2.25 x 10^6 J kg-1

m=0.89kg

3 0
3 years ago
chegg 2. What pattern did you observe measuring cell voltages with a silver electrode versus with a platinum/H2 electrode
Eduardwww [97]

chegg 2. What pattern did you observe measuring cell voltages with a silver electrode versus with a platinum/H2 electrode There is a difference of -0.786 V in silver

<h3>What is cell voltages ?</h3>

The difference in electric potential between two points, also known as voltage, electric potential difference, electric pressure, or electric tension, is what determines how much labor is required to move a test charge between the two sites in a static electric field. Volt is the name of the derived unit for voltage (potential difference) in the International System of Units. Joules per coulomb, or 1 volt equals 1 joule (of work) for 1 coulomb, is how work per unit charge is stated in SI units (of charge). The quantum Hall and Josephson effect was first employed in the 1990s, and most recently (in 2019), fundamental physical constants have been added for the definition of all SI units and derived units. Power and current were used in the previous SI definition for volt.

To learn more about  cell voltages from the given link:

brainly.com/question/18938125

#SPJ4

7 0
2 years ago
A chemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. The vessel is
Anuta_ua [19.1K]

The maximum safe operating temperature for this reaction is equal to 895°C.

<u>Given the following data:</u>

  • Width of cylinder = 22 cm.
  • Height, h = 26.4 cm.
  • Maximum safe pressure = 6.30mpa.
  • Mass = 0.537 kg.

<u>Scientific data:</u>

  • Ideal gas constant, R = 8.314 L-kPa/Kmol.
  • Molar mass of of dinitrogen monoxide (N_2F_2) gas = 66 g/mol.

Radius, r = \frac{width}{2} =\frac{22}{2} =11\;cm

<h3>How to calculate the maximum safe operating temperature.</h3>

First of all, we would determine the volume of the stainless-steel cylinder by using this formula:

V=\pi r^2 h\\\\V = 3.142 \times 11^2 \times 26.4\\\\

Volume, V = 10,036.81 cm^3.

In liters, we have:

Volume, V = 10.04 Liters.

Next, we would determine the number of moles of dinitrogen monoxide (N_2F_2) gas:

Number \;of \;moles = \frac {mass}{molar\;mass}\\\\Number \;of \;moles = \frac {537}{66}

Number of moles = 8.136 moles.

Now, we can solve for the maximum safe operating temperature by applying the ideal gas equation:

PV=nRT\\\\T=\frac{PV}{nR} \\\\T=\frac{6.30 \times 10^3 \times 10.04}{8.136 \times 8.314}\\\\T=\frac{60541.2}{67.6427}

T = 895.02 ≈ 895°C.

Read more on temperature here: brainly.com/question/24769208

5 0
3 years ago
Which force controls the size of an atomic nucleus?.
klemol [59]

Answer:

strong nuclear force

Explanation:

1, a force that acts on charged particles

2, a force that holds atomic nuclei together

3, gravity, weak nuclear, electromagnetic, strong nuclear

4, strong nuclear force

5, Gravity and the electromagnetic force have infinite ranges while the nuclear forces have very small ranges.

100% :)

3 0
2 years ago
2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'
Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

\displaystyle M_1V_1= M_2V_2

Where <em>M</em> represents molarity and <em>V</em> represents volume.

Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:

\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}

Convert this value to mL:
\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

8 0
2 years ago
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