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3 years ago

What do the three types of mixtures have in common? (colloid, solution, suspension)

Chemistry

1 answer:

trasher [3.6K]3 years ago

6 0

Answer:

A colloid is a heterogeneous mixture in which the dispersed particles are intermediate in size between those of a solution and a suspension. The particles are spread evenly throughout the dispersion medium, which can be a solid, liquid, or gas.

Explanation:

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n order to balance the following reaction S n+Cl 2→ S nCl 4, which coefficient should be inserted in front of chlorine?

victus00 [196]

Answer:

The coefficient that should be inserted in front of chlorine is 2

Explanation:

Sn + 2Cl₂ → SnCl₄

As we have 4 atoms of chlorine in product side, we need 4 Cl in reactant side.

Chlorine is a diatomic atom, so if we have 2 mol of it, we are having 4 atoms of Cl.

The law of conservation of mass must be respected in every chemical equation

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3 years ago

During photosynthesis, plant cells use sunlight as an energy source; animal cells cannot do this. What substance do Animal cells

8090 [49]

Answer:

Chlorophyll

Explanation:

Photosynthesis is the process through which plant cells use carbon dioxide & water to create oxygen & energy rich organic compounds. They do so by converting sunlight ie light energy into chemical energy. This is possible due to presence of chlorophyll in them. Animals can't do so, as they dont have chlorophyll.

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3 years ago

How many molecules of nitrogen gas are in 22.4 L?

Serhud [2]

The answer is letter (B).

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3 years ago

Read 2 more answers

g If 50.0 mL of a 0.75 M acetic acid solution is titrated with 1.0 M sodium hydroxide, what is the pH after 10.0 mL of NaOH have

V125BC [204]

Answer:

pH = 2.66

Explanation:

Acetic Acid + NaOH → Sodium Acetate + H₂O

First we calculate the number of moles of each reactant, using the given volumes and concentrations:

0.75 M Acetic acid * 50.0 mL = 37.5 mmol acetic acid

1.0 M NaOH * 10.0 mL = 10 mmol NaOH

We calculate how many acetic acid moles remain after the reaction:

37.5 mmol - 10 mmol = 27.5 mmol acetic acid

We now calculate the molar concentration of acetic acid after the reaction:

27.5 mmol / (50.0 mL + 10.0 mL) = 0.458 M

Then we calculate [H⁺], using the following formula for weak acid solutions:

[H⁺] = $\sqrt{C*Ka}=\sqrt{0.458M*1.76x10^{-5}}$

[H⁺] = 0.0028

Finally we calculate the pH:

pH = -log[H⁺]

pH = 2.66

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3 years ago

5. Why did you categorize the reactions the way you did? What do your physical reactions have in common? What do your chemical r

lapo4ka [179]

Answer:

What r u trying to ask? you need to put more stuff in your question on here so we can answer it.

Explanation:

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3 years ago