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Vilka [71]
1 year ago
10

helium and hydrogen gas are at an unknown ambient temperature, x. given this information, fill in the blanks below. simplify you

r answers whenever possible. write any numbers with three significant figures
Chemistry
1 answer:
kifflom [539]1 year ago
8 0

Hydrogen and helium are the lightest elements in the periodic table.

<h3>What is helium and hydrogen made of?</h3>
  • Hydrogen and helium are uniformly mixed and form a layer on the surface of gas giants.
  • Scientists predicted in the 1970s that the two lightest elements might separate and form a region of demixing or immiscibility at the high temperatures and pressures found inside gas giants.
  • They are the two most prevalent elements in the universe and are gases at room temperature, with hydrogen constituting roughly 75% of all matter.
  • A helium atom consists of a nucleus with two neutrons and two positively charged protons, which is surrounded by two negatively charged electrons in orbit.
  • One proton and one electron make up one hydrogen atom.

translational = 3

rotational = 2

vibrational = 1

Total = 6

Internal energy = 6N  x 1 /2 k T where N is no of molecules

E₁ = 3 N kT

At the temperature of 1000K , helium  will have following degree of freedom

translational = 3

rotational = 0

vibrational =  0

Total = 3

Internal energy = 3N  x 1 /2 k T where N is no of molecules

E₂ = 3 / 2 N kT

Ratio =  E₁ / E₂

=  2

Learn more about helium and hydrogen refer to:

brainly.com/question/17583402

#SPJ4

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How many grams would 3.36 × 1023 molecules of copper (II) sulfate (CuSO4) weigh?
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Molar mass ( CuSO₄) = 159.609 g/mol

159.609 g ----------------- 6.02 x 10²³ molecules
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mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³

mass = 5.36 x 10²⁴ / 6.02 x 10²³

mass = 8.90 g 

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3 years ago
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According to our textbook, write the formula for the anhydrous compound that was part of the mixture called natron that was used
bearhunter [10]

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The formula for the anhydrous compound that was part of the mixture called natron that was used by the Egyptians is Na2(CO3)10(H2O).

They use this compound for medicine, cookery, agriculture, in glass-making and to dehydrate egyptian mummies.

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8 0
3 years ago
A solution of 100.0 mL of 0.200 M KOH is mixed with a solution of 200.0 mL of 0.150 M NiSO4. (a) Write the balanced chemical equ
NISA [10]

Answer:

a) 2KOH + NiSO₄ → K₂SO₄ + Ni(OH)₂

b) Ni(OH)₂

c) KOH

d) 0.927 g

e) K⁺=0.067 M, SO₄²⁻=0.1 M, Ni²⁺=0.067 M

Explanation:

a) The equation is:

2KOH + NiSO₄ → K₂SO₄ + Ni(OH)₂   (1)        

b) The precipitate formed is Ni(OH)₂  

 

c) The limiting reactant is:

n_{KOH} = V*M = 100.0 \cdot 10^{-3} L*0.200 mol/L = 0.020 moles

n_{NiSO_{4}} = V*M = 200.0 \cdot 10^{-3} L*0.150 mol/L = 0.030 moles

From equation (1) we have that 2 moles of KOH react with 1 mol of NiSO₄, so the number of moles of KOH is:

n = \frac{2}{1}*0.030 moles = 0.060 moles                  

Hence, the limiting reactant is KOH.  

d) The mass of the precipitate formed is:

n_{Ni(OH)_{2}} = \frac{1}{2}*n_{KOH} = \frac{1}{2}*0.020 moles = 0.010 moles

m = n*M = 0.010 moles*92.72 g/mol = 0.927 g  

e) The concentration of the SO₄²⁻, K⁺, and Ni²⁺ ions are:

C_{K^{+}} = \frac{2*\frac{1}{2}*n_{KOH}}{V} = \frac{0.020 moles}{0.300 L} = 0.067 M  

C_{SO_{4}^{2-}} = \frac{\frac{1}{2}*n_{KOH + (0.03 - 0.01)}}{V} = \frac{0.030 moles}{0.300 L} = 0.1 M

C_{Ni^{2+}} = \frac{0.020 moles}{0.300 L} = 0.067 M

I hope it helps you!                                                                        

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<h2><em>hope my answer is useful..</em></h2><h2><em>hope my answer is useful.. </em></h2>

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