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shtirl [24]
3 years ago
8

A bus traveled 280 kilometers between two cities . It left the first city at 3:00 p.m. and arrived at the second city at 7:00 p.

m. What was the average speed of the bus during the trip ?
Chemistry
1 answer:
jeyben [28]3 years ago
7 0

<u>Answer:</u>

70 kilometers per hour

<u>Explanation:</u>

280 kilometers ÷ 4 hours (7:00 pm - 3:00 pm = 4 hours) = 70 kilometers per hour

<em>Hope this helps! Sorry if wrong. You are loved and you are beautiful/handsome!</em>

-Bee

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Define motion of particles in matter
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Explanation:

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5 0
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Evgesh-ka [11]

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3 years ago
The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c
netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is 4.58\times 10^{-3}M

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of oxygen gas

C_2\text{ and }p_2 are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used:  1 atm = 760 torr

C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm

Putting values in above equation, we get:

\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M

Hence, the solubility of oxygen gas at 628 torr is 4.58\times 10^{-3}M

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3 years ago
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4) nature of reactants.
5 0
2 years ago
Will give brainliest to best answer..
Tasya [4]
I have attached the answer here. hope this helps!

let me know if you have any question

6 0
3 years ago
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