Answer:
sp³
Explanation:
The Lewis structure of SCl₂ is shown below.
The central S atom has two lone pairs and two bonding pairs, for four electron groups.
VSEPR theory predicts that the electron geometry is <em>tetrahedral</em>.
This corresponds to the use of sp³ hybrid orbitals.
Answer:
some bonds are broken and new ones are formed. Now you are ready to learn more about those bonds. Chemical bonds are attractions between atoms. They are simply attractive forces (between the + nucleus of one atom and the - electrons of a neighboring atom) that hold groups of atoms together and make them function as a unit.
Answer:
eight strong bonds to the atoms that it touches and six weaker bonds to the atoms it almost touches. This makes it easier to understand why a metal might prefer the body-centered cubic structure to the hexagonal or cubic closest-packed structure.
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The magnitude of dispersion forces in Br2 is greater than the magnitude of dispersion forces in Cl2.
Atomic radius decreases across the period but increases down the group. As more shells are added to the atom, the repulsion between electrons increases. Across the group, more electrons are added without increase in the number of shell hence atomic radius decreases across the period due to increase in the size of the nuclear charge. Therefore, the atomic radius of Li is larger than that of Be.
Ionization energy is a periodic trend that increases across the period but decreases down the group. Since the outermost electron is further from the nucleus due to screening of inner electrons, ionization energy decreases down the group. Across the period, the size of the nuclear charge increases hence ionization energy increases across the period.
For K, the second electron is removed from an inner shell which requires a very large amount of energy. In Ca, the second electron is removed from the valence shell which requires a lesser amount of energy. Therefore, the second ionization energy of K is greater than the second ionization energy of Ca.
The carbon to carbon bond in C2H4 is a double bond which has a greater bond enthalpy than the single bond in C2H6. As such, the carbon to carbon bond in C2H4 has a greater bond energy than the carbon to carbon bond in C2H6.
The boiling point of Cl2 is lower than the boiling point of Br2 because Br2 is larger than Cl2 hence the magnitude of dispersion forces in Br2 is greater than the magnitude of dispersion forces in Cl2.
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