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Basile [38]
3 years ago
7

List at least two chemical reactions that resulted in a white precipitate. For these reactions list the possible chemical name o

f the precipitate. What do these reactions (and the others with white precipitates) have in common?
Chemistry
1 answer:
Alina [70]3 years ago
8 0
Barium chloride + sodium sulphate --> barium sulphate + sodium chloride
BaCl2 + Na2SO4 ---> BaSO4 + 2 NaCl
The barium sulphate appears as a white precipitate

Silver nitrate +  Sodium chloride ---> Silver Chloride + sodium nitrate
AgNO3 + NaCl ----> AgCl + NaNO3
The silver chloride appears as a white precipitate.

These  are sometimes called double decomposition reactions.
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Given 25.43 g of O2 gas, how many liters of gas will you have at STP?<br><br>Answer value
Paraphin [41]

Given :

Mass of O₂, m = 25.43 g.

To Find :

How many liters of gas will you have at STP.

Solution :

Molecular mass of O₂, M.M = 2 × 16 gram/mole

M.M = 32 gram/mole

Number of moles is given by :

n = m/M.M

n = 25.43/32 mole

n = 0.79 mole

Hence, this is the required solution.

4 0
3 years ago
Nitrogen monoxide and water react to form ammonia and oxygen, like this: (g)(g)(g)(g) Write the pressure equilibrium constant ex
xxTIMURxx [149]

Answer:

Kp = \frac{P(NH_{3}) ^{4} P(O_{2}) ^{5}}{P(NO) ^{4} P(H_{2}O)^{6}}

Explanation:

First, we have to write the balanced chemical equation for the reaction. Nitrogen monoxide (NO) reacts with water (H₂O) to give ammonia (NH₃) and oxygen (O₂), according to the following:

NO(g) + H₂O(g) → NH₃(g) + O₂(g)

To balance the equation, we add the stoichiometric coefficients (4 for NH₃ and NO to balance N atoms, then 6 for H₂O to balance H atoms and then 5 for O₂ to balance O atoms):

4 NO(g) + 6 H₂O(g) → 4 NH₃(g) + 5 O₂(g)

All reactants and products are in the gaseous phase, so the equilibrium constant is expressed in terms of partial pressures (P) and is denoted as Kp. The Kp is expressed as the product of the reaction products (NH₃ and O₃) raised by their stoichiometric coefficients (4 and 5, respectively) divided into the product of the reaction reagents (NO and H₂O) raised by their stoichiometric coefficients (4 and 6, respectively). So, the pressure equilibrium constant expression is written as follows:

Kp = \frac{P(NH_{3}) ^{4} P(O_{2}) ^{5}}{P(NO) ^{4} P(H_{2}O)^{6}}

6 0
3 years ago
If 42.8 mL of 0.204 M HCl solution is needed to neutralize a solution of Ca(OH)2, how many grams of Ca(OH)2 must be in the solut
Aneli [31]

Hey There!

At neutralisation moles of H⁺ from HCl  = moles of OH⁻ from Ca(OH)2  so :

0.204 * 42.8 / 1000  => 0.0087312 moles

Moles of Ca(OH)2 :

2 HCl + Ca(OH)2 = CaCl2 + 2 H2O

0.0087312 / 2 => 0.0043656 moles (  since each Ca(OH)2 ives 2 OH⁻ ions )

Therefore:

Molar mass Ca(OH)2 = 74.1 g/mol

mass = moles of Ca(OH)2 * molar mass

mass =  0.0043656 * 74.1

mass = 0.32 g of Ca(OH)2


Hope that helps!

6 0
3 years ago
If you had excess chlorine, how many moles of of aluminum chloride could be produced from 19.0 g of aluminum?
SIZIF [17.4K]
The chemical reaction would be written as follows:

2Al + 3Cl2 = 2AlCl3

We are given the amount of aluminum to be used in the reaction. This will be the starting point of the calculations. We do as follows:

19.0 g Al ( 1 mol / 29.98 g ) ( 2 mol AlCl3 / 2 mol Al ) = 0.63 mol AlCl3
5 0
3 years ago
Read 2 more answers
What is the specific heat of titanium in j/(g⋅∘c) if it takes 89.7 j to raise the temperature of a 33.0 g block by 5.20 ∘c?
larisa [96]
Specific  heat  capacity  is  the  amount  of  energy  required  to  raise one  gram  of  substances by 1 degree  celsius .  Therefore  specific  heat  capacity  for  tatanium  is  89.7j /(  33.0g  x5.2 degree celsius) = 0.52j/g  degree celcius
Molar mass for tatanium   is  47.9 g/mole
heat  is  therefore 47.9  g/mole  x 0.52j/g  =24.9j/mole
5 0
3 years ago
Read 2 more answers
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