Answer:
1. 67.2 kJ/mol
Explanation:
Using the derived expression from Arrhenius Equation

Given that:
time
= 8.3 days = (8.3 × 24 ) hours = 199.2 hours
time
= 10.6 hours
Temperature
= 0° C = (0+273 )K = 273 K
Temperature
= 30° C = (30+ 273) = 303 K
Rate = 8.314 J / mol
Since 
Then we can rewrite the above expression as:








Answer:
0.04 M is the lowest concentration of chloride ions that would be needed to begin precipitation.
Explanation:
Concentration of lead nitarte = ![[Pb(NO_3)_2]=0.010 M](https://tex.z-dn.net/?f=%5BPb%28NO_3%29_2%5D%3D0.010%20M)

1 Mole of lead nirate gives 1 mole of lead ion.
Concentration of lead ion in the solution = 

Concentration of chloride ions = ![[Cl^-]](https://tex.z-dn.net/?f=%5BCl%5E-%5D)
The value of ![K_{sp} for [tex]PbCl_2= 1.6\times 10^{-5}](https://tex.z-dn.net/?f=K_%7Bsp%7D%20for%20%5Btex%5DPbCl_2%3D%201.6%5Ctimes%2010%5E%7B-5%7D)
![K_{sp}=[Pb^{2+}][Cl^{-}]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BCl%5E%7B-%7D%5D%5E2)
![1.6\times 10^{-5}=0.010 M\times [Cl^{-}]^2](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E%7B-5%7D%3D0.010%20M%5Ctimes%20%5BCl%5E%7B-%7D%5D%5E2)
![[Cl^-]=0.04 M](https://tex.z-dn.net/?f=%5BCl%5E-%5D%3D0.04%20M)
0.04 M is the lowest concentration of chloride ions that would be needed to begin precipitation.
Answer:
Spiders and ground beetles.
Why is Anthony so mean? Don't hurt the beetles!
1000 liters = 1 m^3
and
1.3um^3 = 1.3x10^(-6)m^3
multiply both sides of the first equation by 1.3x10^(-6)
1.3x10^(-6) * 1000 liters = 1.3x10^(-6) * 1m^3
1.3x10^(-3) liters = 1.3x10^(-6) m^3