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lesantik [10]
3 years ago
14

Work output of a large machine in a factory is 89,000 joules, and it’s input is 102,000 joules. Work output of a similar machine

is 92,000 joules, and it’s work input is 104,000 joules. Which machine has a greater efficiency
Physics
2 answers:
mojhsa [17]3 years ago
7 0
(89000/102000)×100
=87.25%

(92000/104000)×100
=88.46%

efficiency is (output/input)×100
if u get confused which way input and output should go, remember the smaller value is always output and it's above in the fraction, then only it's possible to get a efficiency lower than 100.

kotegsom [21]3 years ago
3 0

Answer:

The machine with work input of 104,000Joules and work output of 92,000 has the greater efficiency

Explanation:

Efficiency of a machine is the ratio of work done by a machine(work output) to work put in the machine (work input).

Mathematically,

Efficiency = Work output/Work Input ×100

For the machine with work output of 89,000Joules and work input of 102,000Joules, its efficiency will be;

Efficiency = 89,000/102,000×100

Efficiency = 87.5%

Similarly for the other machine with work output of 92,000Joules and work input of 104,000Joules, its efficiency will be;

Efficiency = 92,000/104,000×100

Efficiency = 88.5%

Comparing the efficiency of both machines, the machine with efficiency of 88.5% has greater efficiency.

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A man stands on a platform that is rotating at 3.8 rpm; his arms are outstretched and he holds a brick in each hand. The rotatio
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Answer:

a) 5.197rev/s

b) Kf/Ki =2.28

Explanation:

a) Angular momentum of the system L = Iw

ButLi=Lf

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b)Kinetic energy KE= 0.5Iw^2

Ki = 0.5Iiwi^2

Kf=0.5Ifwf^2

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A hovering mosquito is hit by a raindrop that is 50 times as massive and falling at 8.4 m/s, a typical raindrop speed. How fast
kenny6666 [7]

The final velocity after the collision is 8.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, if we consider the system to be isolated (=no external unbalanced forces), the total momentum of the raindrop+mosquito must be conserved before and after the collision.

If the collision is perfectly inelastic, moreover, the raindrop and the mosquito stick together and travel at the same velocity v after the collision.

Mathematically:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 is the mass of the first mosquito

u_1 = 0 is the initial velocity of the mosquito

m_2 = 50 m_1 is the mass of the raindrop

u_2 = 8.4 m/s is the initial velocity of the raindrop

v is the final combined velocity of the raindrop+mosquito

Re-arranging the equation and substituting, we find:  

m_1 u_1 + 50 m_1 u_2 = (m_1 + 50 m_1) v\\50 m_1 u_2 = 51 m_1 v\\50 u_2 = 51 v\\v=\frac{50}{51}u_2 = \frac{50}{51}(8.4)=8.2 m/s

Learn more about momentum here:

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MariettaO [177]

Explanation:

the weight of the people inside the bus

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