12.5 mL of NaOH solution
Explanation:
We have the following chemical reaction in which sodium hydroxide (NaOH) react with acetic acid (CH₃-COOH) to form sodium acetate (CH₃-COONa) and water (H₂O):
NaOH + CH₃-COOH → CH₃-COONa + H₂O
molar concentration = number of moles / volume
number of moles = molar concentration × volume
number of moles of CH₃-COOH = 0.2 × 12.5 = 2.5 mmoles
*typically a vinegar solution have a concentration of acetic acid of 12.5 mol/L.
Taking in account the chemical reaction, we devise the following reasoning:
if 1 mmole of NaOH reacts with 1 mmole of CH₃-COOH
then X = 2.5 mmoles of NaOH reacts with 2.5 mmoles of CH₃-COOH
volume = number of moles / molar concentration
volume of NaOH solution = 2.5 / 0.2 = 12.5 mL
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molar concentration
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Answer:
A: 92.02 g
Explanation:
Equation of the reaction;
N2 (g)+ 2O2(g)------> 2NO2(g)
Note that the balanced reaction equation is the first step in solving any problem on stoichiometry. Once the reaction equation is correct, the question can be easily solved...
Answer
is: the final pressure of the gas is closest to 3,17 atm.
<span><span>
p</span>₁ =
3,2 atm.</span><span>
T₁ =
310 K.</span><span>
V₁ =
6 L.</span><span>
p₂ = ?</span><span>
T₂ =
410K.</span><span>
V₂ = 8,0 L.</span><span>
<span>Use combined gas law - the volume of amount of gas is proportional to the ratio of
its Kelvin temperature and its pressure.</span><span>
p</span></span><span>₁V₁/T₁ =
p₂V₂/T₂.</span><span>
<span>3,2 atm · 6,0 L ÷ 310 K = p</span>₂ · 8,0 L ÷ 410 K.</span><span>
0,0619 = 0,0195p</span><span>₂.</span><span>
p</span><span>₂ =
3,17 atm.</span>
Answer:
When an acid reacts with a metal, what is one of the usual products?
<u><em>C) Hydrogen gas</em></u>
Explanation:
