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Ierofanga [76]
3 years ago
15

Pick the selection that increases in energy.

Chemistry
1 answer:
RUDIKE [14]3 years ago
8 0

Answer:

i think mix im um 1s 6f 4d is correct answer

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A student was given four unknown solutions. Each solution was checked for. conductivity and tested with. phenolphthalein. The re
777dan777 [17]

Answer: (3) C

Explanation:

4 0
3 years ago
Write a balanced equation for the complete combustion of 2,3-dimethylbutane. use the molecular formula for the alkane (c before
Nuetrik [128]

2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O

<em>Step 1</em>. Write the <em>condensed structural  formula</em> for 2,3-dimethylbutane.

(CH_3)_2CHCH(CH_3)_2

<em>Step 2</em>. Write the <em>molecular formula</em>.

C_6H_14

<em>Step 3</em>. Write the <em>unbalanced chemical equation</em>.

C_6H_14 + O_2 → CO_2 + H_2O

<em>Step 4</em>. Pick the <em>most complicated-looking formula</em> (C_6H_14) and balance its atoms (C and H).

<em>1</em>C_6H_14 + O_2 → <em>6</em>CO_2 + <em>7</em>H_2O

<em>Step 5</em>. Balance the <em>remaining atoms</em> (O).

1C_6H_14 + (<em>19/2</em>)O_2 → 6CO_2 + 7H_2O

Oops! <em>Fractional coefficients</em>!

<em>Step 6</em>. <em>Multiply all coefficients by a number</em> (2) to give integer coeficients..

2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O

4 0
3 years ago
Read 2 more answers
How can atoms be neutral if they contain charged particles?
rewona [7]
Stability of atoms is determined by neutron:proton ratio. This n/p ratio is 1:1 for elements below atomic number 20. Hope this helps.
4 0
3 years ago
Consider the following reaction at constant pressure. Use the information provided below to determine the value of ΔS at 473 K.
Elis [28]

Answer:

The reaction will be spontaneous

Explanation:

To determine if the reaction will be spontaneous or not at this temperature, we need to calculate the Gibbs's energy using the following formula:

\Delta G= \Delta H - T * \Delta S

<u>If the Gibbs's energy is negative, the reaction will be spontaneous, but if it's positive it will not.</u>

Calculating the \Delta G= -1267 - 473 K* \Delta S :

\Delta G= -1267 - 473 K* \Delta S

Now, other factor we need to determine is the sign of the S variation. When talking about gases, the more moles you have in your system the more enthropic it is.

In this reaction you go from 7 moles to 8 moles of gas, so you can say that you are going from one enthropy to another higher than the first one. This results in: \Delta S>0[/tex}Back to this expression: [tex]\Delta G= -1267 - 473 K* \Delta S

If the variation of S is positive, the Gibbs's energy will be negative always and the reaction will be spontaneous.

4 0
3 years ago
On the periodic table, periods are elements with similar
Vladimir [108]

Answer:

B.) Atomic Properties

can I have brainliest?

Have\\a\\nice\\day

<h2 />

3 0
2 years ago
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