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yan [13]
4 years ago
7

Someone plz help me ASAP PLZ PLZ PLZZZZ

Mathematics
2 answers:
baherus [9]4 years ago
8 0

Answer:

divide

Step-by-step explanation:

................

Gemiola [76]4 years ago
5 0
You have to divide



i think so
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Plz answer rn nmmmm ASAP!!
notka56 [123]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
Please help ASAP for question b
zlopas [31]

Answer: The height of the new player is 210 cm

Step-by-step explanation: The previous mean of the entire team has been calculated as 200.3

What this means is that, we have a summation of the observed data and a summation of the frequency of data.

The mean was calculated as

Sum FX/Sum F = 200.3

Where Sum FX is 2604 and Sum F is 13

However, our calculation should now read thus,

Sum FX/Sum F = 201 {where 201 is the new mean}

By cross multiplication we now have

Sum FX = Sum F x 201

Remember that a new member has joined the team so our Sum F is now 14 and we can now express it as thus

Sum FX = 14 x 201

Sum FX = 2814

If the summation of the observed data after adding a new team member is now 2814, then the addition to the previous observed data would be

2814 - 2604 = 210

So the height of the new member added to the team is 210 cm.

6 0
4 years ago
If 120% is £360, what is 100%?
Lunna [17]

Answer:

300

Step-by-step explanation:

To get from 120% to 100% you divide by 1.2  360/1.2=300 :)

5 0
2 years ago
4c=-40 i don't know this and i need help<br> ill do what i can in return
melamori03 [73]

Answer:

4c=-40

Divide boyh sides by 4

c=-40/4

c=-10

8 0
3 years ago
Read 2 more answers
Given the function g(x) = 6(4)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.
Mademuasel [1]

We are given the function:

g(x) = 6 (4)^x

 

Part A.

To get the average rate of change, we use the formula:

average rate of change = [g(x2) – g(x1)] / (x2 – x1)

 

Section A:

average rate of change = [6 (4)^1 – 6 (4)^0] / (1 – 0) = 18

 

Section B:

average rate of change = [6 (4)^3 – 6 (4)^2] / (3 – 2) = 288

 

Part B.

288 / 18 = 16

Therefore the average rate of change of Section B is 16 times greater than in Section A.

 

<span>The average rate of change is greater between x = 2 to x = 3 than between x = 1 and x = 0 because an exponential function's rate of change increases with increasing x (not constant).</span>

8 0
4 years ago
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