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statuscvo [17]
3 years ago
6

Please help me?!!!!!!!

Chemistry
2 answers:
Vera_Pavlovna [14]3 years ago
6 0
I think it’s True cuz earth divides it into two equal halves
SCORPION-xisa [38]3 years ago
4 0

Answer:

this is true! good luck!

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How many diatomic molecules are there? List all of them
wariber [46]

Answer: Br2 I2 N2 Cl2 H2 O2 F2 (7 elements)

Explanation:

How to remeber this: Hal-NOH or BrINCIHOF

halogens Nitrogen, Oxygen, and Hydrogen.

7 0
3 years ago
I need help with these 4
storchak [24]

Rift Valley Examples

  • East African
  • Rhine Rift Valley (Germany)
  • Baikal Rift Valley (Russia)

Rift Valley Facts/Characteristics

  • Bordered by fault zones and separating land masses
  • A portion of land that drops, forming a valley.
  • Formed as tectonic plates move.

Fossils - Examples

  • Bones
  • Shells
  • Exoskeletons
  • Stone imprints of animals.

Non Examples of Fossils

  • Stones
  • rocks
  • Some bones (If they are fossils they will be a lot heavier than other bones.

Hope this helps.

5 0
3 years ago
Why is the electrical charge of an atom zero or neutral?
kompoz [17]
Because the atom isn't a isotope. The electrons, (negative charge) , and the protons, (positive charge), balance each other out. 
8 0
3 years ago
What is true about most of the wavelengths found in the electromagnetic spectrum?
olasank [31]
D, you can't see ultraviolet rays and other similar frequency waves with the naked eye.
7 0
2 years ago
What is the wavenumber of the radiation emitted when a hydrogen
LUCKY_DIMON [66]

Answer: Wavenumber of the radiation emitted  is 0.08\times 10^{8}m^{-1}

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

E=\frac{hc}{\lambda}

where,

E = energy of the radiation = 1.634\times 10^{-18}J

h = Planck's constant  = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of radiation = ?

Putting values in above equation, we get:

1.634\times 10^{-18}J=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{\lambda}\\\\\lambda=12.16\times 10^{-8}m

\bar {\nu}=\frac{1}{\lambda}=\frac{1}{12.16\times 10^{-8}}=0.08\times 10^{8}m^{-1}

Thus wavenumber of the radiation emitted  is 0.08\times 10^{8}m^{-1}

8 0
3 years ago
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