The limiting reagent is Copper (Cu)
First, balance the reaction before determining the limiting reactant.
Cu + 2Ag
Cu(NO3)2 + 2Ag from NO3
Take the beginning material amount and calculate the number of moles of one of the products to identify the limiting reactant. The limiting reactant is the one that produces a product with the fewest moles.
5.50×1.00/2.00=2.75
The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced. Calculate how many moles of each reactant are present and contrast this ratio with the mole ratio of the reactants in the balanced chemical equation to get the limiting reactant.
Copper is the limiting reactant since there are only 2.50 mol of it and only 2.50 mol of AgNO3 will result from the reaction.
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I think the word your looking for is procedure
Answer:
Na²O (Sodium-oxide)
Explanation:
Physical state - Solid
Appearance - White solid
Solubility - Yes. Formes NaOH
Color - White
Nature - Basic
Answer:
For example, 20mL of stock solution with 80mL of water.
Explanation:
60g of NaOH in 0,300L have a molar concentration of:
60g NaOH × ( 1 mol / 40g) = 1,5 moles of NaOH / 0,300L = 5M
If you want to mix this solution with water to produce a 1M NaOH solution you need to mix 1 part of volume of the stock solution per 5 parts of total volume. For example, mix 20mL of stock solution with 80mL of water. That is:
5M NaOH × ( 20mL stock solution / 20mL + 80mL -Total volume-) = 1M NaOH solution
I hope it helps!
