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3 years ago

Which statement applies to the energy change illustrated in the quantized energy emission diagram

Chemistry

1 answer:

inysia [295]3 years ago

4 0

That would be the electrons and how they jump to level to level.

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Which of the following diatomic gases has the shortest bond between its two atoms?

Sunny_sXe [5.5K]

The correct answer is D. N2

8 0

3 years ago

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HELPPP TODAY IS THE LAST DAY OF SCHOOL

Alecsey [184]

Answer:

orbiting closer to the earth's surface.....im pretty sure abt it

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3 years ago

NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a

Margarita [4]

Answer:

λ = 0.0167 m = 16.7 mm

Explanation:

The wavelength of these radio waves can be found out by using the formula for the speed of radio waves:

v = fλ

where,

v = speed of radio waves = speed of light = 3 x 10⁸ m/s

f = frequency of radio waves = 18 GHz = 18 x 10⁹ Hz

λ = Wavelength = ?

Therefore,

3 x 10⁸ m/s = (18 x 10⁹ Hz)λ

λ = (3 x 10⁸ m/s)/(18 x 10⁹ Hz)

λ = 0.0167 m = 16.7 mm

4 0

2 years ago

What is the ph of a 3x10-8M H+ solution

Lelu [443]

Answer:

The pH of the solution is 7, 52

Explanation:

The pH gives us an idea of the acidity or alkalinity of a solution. Is calculated:

pH = -log (H +)

pH= -log ( 3x10-8)= 7, 52

4 0

3 years ago

If you have 16 g of manganese (II) nitrate tetrahydrate, how much water is required to prepare 0.16 M solution from this amount

Schach [20]

Answer: The amount of water required to prepare given amount of salt is 398.4 mL

Explanation:

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.16 M

Given mass of manganese (II) nitrate tetrahydrate = 16 g

Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol

Putting values in above equation, we get:

$0.16M=\frac{16\times 1000}{251\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{16\times 1000}{251\times 0.16}=398.4mL$

Volume of water = Volume of solution = 398.4 mL

Hence, the amount of water required to prepare given amount of salt is 398.4 mL

4 0

3 years ago