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Natalka [10]
4 years ago
11

Which statement applies to the energy change illustrated in the quantized energy emission diagram

Chemistry
1 answer:
inysia [295]4 years ago
4 0
That would be the electrons and how they jump to level to level.
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Sanjay is learning about the elements that make up Earth’s crust. Ms. Richards, his Earth science teacher, gives him an element
oksano4ka [1.4K]

Answer:

Iron

Hope this helps! Stay safe!

(Plz vote me as brainliest)

3 0
3 years ago
Which two substances are covalent compounds? * C6H12O6(s) and KI(s) C6H12O6(s) and HCl(g) KI(s) and NaCl(s) NaCl(s) and HCl(g)
Ray Of Light [21]

Answer: Option (b) is the correct answer.

Explanation:

A covalent compound is defined as the compound in which sharing of electrons take place between the combining atoms. Generally, when two or more non-metals chemically combine together the it will lead to the formation of a covalent compound.

For example, C_{6}H_{12}O_{6} and HCl is also a covalent compound.

And, a compound in which transfer of electrons occur between the combining atoms is known as an ionic compound. Whenever, a metal chemically combines with a non-metal then it will always lead to the formation of an ionic compound.

For example, KI is an ionic compound.

Thus, we can conclude that C_{6}H_{12}O_{6} and HCl are the two substances which are covalent compounds.

7 0
3 years ago
Since there are many organic compounds,how can you distinguish one organic compound from another​
iogann1982 [59]

What are organic and inorganic compounds? Organic chemistry is the study of the carbon compounding molecules. Inorganic chemistry, by contrast, is the study of all compounds that do NOT contain carbon compounds.

8 0
3 years ago
Calculate the ph of a solution containing 0.0451 m potassium hydrogen tartrate and 0.028 m dipotassium tartrate. The ka values f
Marina86 [1]

Given buffer:

potassium hydrogen tartrate/dipotassium tartrate (KHC4H4O6/K2C4H4O6 )

[KHC4H4O6] = 0.0451 M

[K2C4H4O6] = 0.028 M

Ka1 = 9.2 *10^-4

Ka2 = 4.31*10^-5

Based on Henderson-Hasselbalch equation;

pH = pKa + log [conjugate base]/[acid]

where pka = -logKa

In this case we will use the ka corresponding to the deprotonation of the second proton i.e. ka2

pH = -log Ka2 + log [K2C4H4O6]/[KHC4H4O6]

     = -log (4.31*10^-5) + log [0.0451]/[0.028]

pH = 4.15



4 0
3 years ago
For dessert, she prepares to bake a delicious apple pie. During one of the steps, she
Leno4ka [110]

Answer:

heating the sugar

Explanation:

6 0
3 years ago
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