Answer:
a) 10.7° ≈ 11°
b) 0.19
Explanation:
If the road is banked at an angle, without seeking the help of friction, (i.e. frictionless road), the forces acting on the car are shown in the attached free body diagram to the question
In the y - direction
mg = N cos θ (eqn 1)
mg = weight of the car.
N = normal reaction of the plane on the car
And in the direction parallel to the inclined plane,
(mv²/r) = N sin θ (eqn 2)
(mv²/r) = force keeping the car in circular motion
Divide (eqn 2) by (eqn 1)
(v²/gr) = Tan θ
v = velocity of car = 60 km/h = 16.667 m/s
g = acceleration due to gravity
r = 150 m
(16.667²/(9.8×150)) = Tan θ
θ = Tan⁻¹ (0.18896)
θ = 10.7° ≈ 11°
b) In the absence of banking, the frictional force on the road has to balance the force keeping the car in circular motion
That is,
Fr = (mv²/r)
Fr = μN = μ mg
μ mg = mv²/r
μ = (v²/gr) = (16.667²/(9.8×150)) = 0.19
Hope this Helps!!!
Answer:
Heterogeneous Mixture
Explanation:
Heterogeneous by definition is when two different substance are mixed together, but they are not evenly distributed. In this case, the salad dressing is a Heterogeneous Mixture, for the dressing does not mix completely evenly throughout the salad.
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Answer:
4. Becomes softer as temperature rises
Explanation:
An amorphous solid is any noncrystalline solid in which the atoms and molecules are not organized in a definite lattice pattern. Such solids include glass, plastic, and gel. Solids and liquids are both forms of condensed matter; both are composed of atoms in close proximity to each other.
Sorry im from the UK, ill do my math in metric :)
5) work done = force * distance moved in direction of force
170J = 140N* ?d
170J/140N = 1.21m
F=Ma
140N/9.81ms^-2=
14.27Kg or 31.46Ib
you could do the fast alternative simplified route to this question
as 140/4.45 = 31.46Ib
Answer:
(a) 120 eV
(b) 12.840 keV
(c) 0.466%
Solution:
As per the question:
The potential difference between the dees, V = 120 V
No. of passes, n = 107
Now,
(a) The potential energy can be given as 'qV' but by the principle of conservation of energy, this energy with each pass is converted into the kinetic energy of the particle which is given as 120 eV
Thus
The increase in Kinetic energy, 
(b) Kinetic energy on completion of 107 passes is given by:
(c) The velocity of the particle can be calculated from its kinetic energy:

Thus

Thus radius can be given as:

where
B = Magnetic field
= mass of proton
Therefore, we can write that:

Thus the percentage increase in radius from n = 107 to n = 108 is given by:
= 0.466 %