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Grace [21]
3 years ago
10

If WEIGHT depends on gravity and the pull of gravity

Physics
1 answer:
deff fn [24]3 years ago
4 0

Answer:

The weight will be more on planet B because greater is the gravity more is the weight of a body

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a block (mass 0.6kg) is released from rest at point A at the top of a ramp inclined at 36.9 degress above the horizontal. The bl
bija089 [108]
14.136 J as shown on the photo with two thought processes but overall same calculation

3 0
3 years ago
If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released, it oscillates. Suppose
Volgvan

Answer:

a) A=0.125 m

b) T = 1.72 s

c) f= 0.58 Hz

Explanation:

a) As we are told that the maximum displacement from the equilibrium position was 0.125 m (from which it was released at zero initial speed), this is the amplitude of the resultant SHM, so, A=0.125 m

b) In order to find the period, we must get the total time needed to complete a full cycle (which means that the block must pass twice through the equilibrium point). We are told that at t=0.860 sec, the block has reached to the other end of the trajectory, and it  has passed through the equilibrium point only once.

This means that the period must be exactly the double of this time:

T = 2*0. 860 sec = 1.72 sec.

c) In a SHM, the frequency is defined just as the inverse of the period (like in a uniform circular movement), so we can get the frequency  f as follows:

f = 1/T = 1/ 1.72 s= 0.58 Hz

8 0
3 years ago
A proton enters a region of constant magnetic field, perpendicular to the field and after being accelerated from rest by an elec
kicyunya [14]

Answer:

 B = 1.1413 10⁻² T

Explanation:

We use energy concepts to calculate the proton velocity

starting point. When entering the electric field

        Em₀ = U = q V

final point. Right out of the electric field

        em_f = K = ½ m v²

energy is conserved

       Em₀ = Em_f

       q V = ½ m v²

       v = \sqrt{2qV/m}

we calculate

       v = \sqrt{\frac{ 2 \ 1.6 \ 10^{-19} \ 300}{1.67 \ 0^{-27}} }

       v = \sqrt{632.3353 \ 10^8}

       v = 25.15 10⁴ m / s

now enters the region with magnetic field, so it is subjected to a magnetic force

        F = m a

the force is

       F = q v x B

as the velocity is perpendicular to the magnetic field

       F = q v B

acceleration is centripetal

       a = v² / r

we substitute

       qvB =1/2  m v² / r

       B =  v\frac{m v}{2 q r}

we calculate

       B = \frac{1.67 \ 10^{-27} 25.15 \ 10^4 }{1.6 \ 10^{-19} 0.23}

       B = 1.1413 10⁻² T

8 0
3 years ago
why can we use P=VI in the question electric bulb base generator is rated 220 volts and 100W when it is operated on 110v what wi
MrRissso [65]

Answer:

Correct answer:  P₂ = 25 W

Explanation:

Given: voltage V₁ = 220 V, power P₁ = 100 W, V₂ = 110 V, P₂ = ?

The formula for calculating power is:

P = V · I

We will include in the story and ohm's law:

I = V/R

We will replace the current in the expression for power

P = V · V/R = V²/R  ⇒ R = V²/P

We will first calculate the electrical resistance of the bulb which is a constant in the electrical circuit

R = V₁²/P₁ = 220²/ 100 = 48,400 / 100 = 484 Ω

Power consumption of bulb connected to 110 V is:

P₂ = V₂²/R = 110²/484 = 12,100/484 = 25 W

P₂ = 25 W

God is with you!!!

8 0
3 years ago
How much time would it take a fox to accelerate from 2 m/s to 8 m/s at a rate of 2 m/s/s?
faltersainse [42]

Answer:

read below

Explanation:

uh I might be crazy but there is two ways to solve this a simple way and complexish first understand you are using kinematic equations all 4 are valid for this but you need to know which ones the best choice which is vf=vi + at this should solve for time i would do it for you but I find it better when you plug it in your self your learn much better

3 0
3 years ago
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