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abruzzese [7]
2 years ago
10

What is the resistance of a 3.5 m copper wire (Rho= 1.7x10-8 Ohm·m) that 1 point

Physics
1 answer:
VikaD [51]2 years ago
4 0

Answer:

(D)

Explanation:

Given :

l=3.5 m

A=5.26*10^{-6} m^{2}

p=1.7*10^{-8}  ohm.m

Resistance can be calculated as :

R=p\frac{l}{A} \\R=1.7*10^{-8} \frac{3.5}{5.26*10^{-6} }

R=\frac{5.95*10^{-2} }{5.26} \\R=1.13*10^{-2}

Resistance of the wire will be 1.1×10^{-2} ohms

Option D is correct

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Read 2 more answers
Two blocks, with masses M2&gt;M1, are connected by ropes. You pull to the right on a second rope, with external force "T1".The b
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Answer:

(M_1 + M_2) a > M_2 a

Becuase M_1 +M_2> M_2

So then we can conclude that:

T_1 > T_2

And that makes sense since the force T_1 needs to accelerate the two masses and T_2 just need to accelerate M_2.

So the best option for this case would be:

a. T1 > T2

See explanation below.

Explanation:

For this case we consider the system as shown on the figure attached.

Since the system is connected the acceleration for both masses are equal, that is a_{M_1}= a_{M_2} = a

From the second Law of Newthon we have that the force applied for the mass M_2 is F_{M_2}= M_2 a and we know that the force acting on the x axis for the mass 2 is F_{M_2}= T_2 so then we have that T_2= M_2 a

Now when we consider the system of M_1 +M_2 as a whole mass, this system have the same acceleration a and on this case we will see that the only force acting on the entire system would be T_1 and then by the second law of Newton we have that:

F_{M_1 +M_2} = T_1 = (M_1 +M_2) a

And then if we compare T_1 and T_2 we see that :

(M_1 + M_2) a > M_2 a

Becuase M_1 +M_2> M_2

So then we can conclude that:

T_1 > T_2

And that makes sense since the force T_1 needs to accelerate the two masses and T_2 just need to accelerate M_2.

So the best option for this case would be:

a. T1 > T2

6 0
2 years ago
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