Answer:
<u>: WHY DIDN'T THE POD DOCK LIKE IT WAS SUPPOSED TO DO?</u><u> </u>
<u>ANSWER</u><u>;</u>
The force exerted by the thrusters caused the pod to change direction.
WHAT NEW THEORIES DO YOU HAVE?
ANSWER;
This pod moved differently because it was more massive.
<em><u>C</u></em><em><u>A</u></em><em><u>R</u></em><em><u>R</u></em><em><u>Y</u></em><em><u>O</u></em><em><u>N</u></em><em><u>L</u></em><em><u>E</u></em><em><u>A</u></em><em><u>R</u></em><em><u>N</u></em><em><u>I</u></em><em><u>N</u></em><em><u>G</u></em><em><u>:</u></em><em><u>)</u></em>
Answer:
Explanation:
mass m = 3 kg
spring constant be k
k x .8 = 40 N
k = 40 / .8 = 50 N /m
angular frequency ω = √ ( k / m )
= √ ( 50 / 3 )
= 4.08 rad /s
Let amplitude of oscillation be A .
1/2 k A² = 1/2 m v²
50 A² = 3 x 1²
A = .245 m = 24.5 cm
For displacement , the equation of SHM is
x = A sinωt
= 24.5 sin4.08 t
x = 24.5 sin4.08 t
Here, angle 4.08 t is in radians .
63783626736377474737377447
It slows the object down so it cannot move well and evetually the object cannot be pushed and farther
Answer:
The work done by the bird is 0.762 J
Explanation:
Given;
force applied by the bird, f = 10 N
distance the bird moved the worm, d = 3 inches = 0.0762 m
The work done by the bird is given by;
W = F x d
where;
W is the work done by the bird
d is the distance the bird moved the load
Substitute the given values and estimate the work done by the bird;
W = 10 x 0.0762
W = 0.762 J
Therefore, the work done by the bird is 0.762 J