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Flura [38]
3 years ago
10

Listed following are several astronomical objects. Rank these objects based on their diameter, from largest to smallest. (Note t

hat the neutron star and black hole in this example have the same mass to make your comparison easier, but we generally expect black holes to have greater masses than neutron stars.)
a.main-sequence star of spectral type a.
b. jupiter.
c. a one solar mass white dwarf.
d. the moon.
e. a two solar mass neutron star.
f. event horizon of a two solar mass black hole.
Physics
1 answer:
daser333 [38]3 years ago
3 0

Answer:

Ranked

Explanation:

The rank of these objects from largest to smallest based on diameter is as follows

1. main-sequence star of a spectral type A

2. Jupiter

3. a one-solar-mass white dwarf

4.the Moon

5. a two-solar-mass neutron star

6. the event horizon of a two-solar-mass black hole

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(d/λ) = 17.67

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(d/λ) = 2/(sin(6.5)

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Determine a formula for the magnitude of the force F exerted on the large block (Mc) so that the mass Ma does not move relative
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Answer:

The magnitude of the force F is given by

F =  (M_{a} + M_{b} + M_{c} ) *(M_{b}*g/(\sqrt{M_{a} ^{2}-M_{b} ^{2}}))

Explanation:

Given there are three blocks of masses M_{a}, M_{b} and M_{c} (ref image in attachment)

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F =  (M_{a} + M_{b} + M_{c} ) *a    ................(equation 1)

Also it is given that M_{a} does not move with respect to M_{c}, which gives tension T  is exerted on pulley  by M_{a} only, Hence tension T is

T = M_{a} *a    ..........(equation 2)

There is also also tension exerted by M_{b}. There are two components here: horizontal due to acceleration a and vertical component due to gravity g. Thus tension is given by

T = M_{b} \sqrt{a^{2} +g^{2} }   ................(equation 3)

From equation 2 and 3, we get

M_{a} *a  = M_{b} \sqrt{a^{2} +g^{2} }  

Squaring both sides we get

M_{a} ^{2} *a^{2} = M_{b} ^{2} * (a^{2}+g^{2})

M_{a} ^{2} *a^{2} = (M_{b} ^{2} * a^{2})+ (M_{b} ^{2} *g^{2})

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Taking square root on both sides, we get acceleration a

a = M_{b}*g/(\sqrt{M_{a} ^{2}-M_{b} ^{2}})

Hence substituting the value of a in equation 1, we get

F =  (M_{a} + M_{b} + M_{c} ) *(M_{b}*g/(\sqrt{M_{a} ^{2}-M_{b} ^{2}}))

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3 years ago
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musickatia [10]

Answer:

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