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Flura [38]
3 years ago
10

Listed following are several astronomical objects. Rank these objects based on their diameter, from largest to smallest. (Note t

hat the neutron star and black hole in this example have the same mass to make your comparison easier, but we generally expect black holes to have greater masses than neutron stars.)
a.main-sequence star of spectral type a.
b. jupiter.
c. a one solar mass white dwarf.
d. the moon.
e. a two solar mass neutron star.
f. event horizon of a two solar mass black hole.
Physics
1 answer:
daser333 [38]3 years ago
3 0

Answer:

Ranked

Explanation:

The rank of these objects from largest to smallest based on diameter is as follows

1. main-sequence star of a spectral type A

2. Jupiter

3. a one-solar-mass white dwarf

4.the Moon

5. a two-solar-mass neutron star

6. the event horizon of a two-solar-mass black hole

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Explanation:

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Answer:

<em>(a) The average velocity is 16 m/s</em>

<em>(b) The acceleration is 0.4 m/s^2</em>

<em>(c) The final velocity is 24 m/s</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity (or the speed) of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, final speed is calculated as follows:

v_f=v_o+at\qquad\qquad [1]

The distance traveled by the object is given by:

\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]

(a) The average velocity is defined as the total distance traveled divided by the time taken to travel that distance.

We know the distance is x=640 m and the time taken t= 40 s, thus:

\displaystyle \bar v=\frac{x}{t}=\frac{640}{40}=16

The average velocity is 16 m/s

Using the equation [1] we can solve for a:

\displaystyle a=\frac{v_f-v_o}{t}

(c) From [2] we can solve for a:

\displaystyle a= 2\frac{x-v_ot}{t^2}

Since vo=8 m/s, x=640 m, t=40 s:

\displaystyle a= 2\frac{640-8\cdot 40}{40^2}=0.4

The acceleration is 0.4 m/s^2

(b) The final velocity is calculated by [1]:

v_f=8+0.4\cdot 40

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The final velocity is 24 m/s

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Explanation:

Below is an attachment containing the solution.

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