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Paraphin [41]
2 years ago
8

How many grams of oxygen are needed to react with excess methane in the following reaction, in order to produce 325 kJ of energy

?
Chemistry
1 answer:
Sergio [31]2 years ago
6 0
~移動NDISとJSが可いままでも今のところ天の
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Imagine you are given a mystery element. It is, however, a discovered and known element. You may perform a maximum of two observ
miv72 [106K]

The classification of it being a metal, nonmetal, or metalliod will be useful in the process of elimination to determine what it is. Then for the second test, meauring the atomin radius will narrow it down quicker to the mystery elemet's name.

Since you determined what part of the periodic table it's on, then when measuring the atomic radius, you should be able to pinpoint what the element is more surely.

6 0
3 years ago
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How many orbitals are contained in the third main energy level and in the fifth energy level
antoniya [11.8K]

There are 9 orbitals in the third energy level and 25 orbitals in the fifth energy level.

I hope this helps you.

5 0
3 years ago
A 40.0 L balloon is filled with air at sea level (1 atm @ 25 oC). It is then tied to a rock and thrown into a cold lake and it s
velikii [3]
To solve this question you need to calculate the number of the gas molecule. The calculation would be:
PV=nRT
n=PV/RT
n= 1 atm * 40 L/ (0.082 L atm mol-1K-<span>1 * 298.15K)
</span>n= 1.636 moles

The volume at bottom of the lake would be:
PV=nRT
V= nRT/P
V= (1.636 mol * 277.15K* 0.082 L atm mol-1K-1 )/ 11 atm= <span>3.38 L</span>
8 0
3 years ago
What is the vitamin in an apple?
bulgar [2K]

Answer:

98 IU

Vitamin A

Explanation:

3 0
3 years ago
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How many atoms are there in 3.559*10^-6 mol of krypton?
algol [13]

Answer:

The answer is

<h2>2.143 \times  {10}^{18}  \:  \: atoms</h2>

Explanation:

To find the number of atoms given the number of moles we use the formula

N = n × L

where

N is the number of entities

n is the number of moles

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

n = 3.559 \times  {10}^{ - 6}  \: mol

Substitute the values into the above formula and solve

That's

<h3>N  = 3.559 \times  {10}^{ - 6}  \times 6.02 \times  {10}^{23}  \\  = 2.1425 \times  {10}^{18}</h3>

We have the final answer as

<h3>N  = 2.143 \times  {10}^{18}  \:  \: atoms</h3>

Hope this helps you

3 0
3 years ago
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