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Citrus2011 [14]
3 years ago
8

If the speed at which an object moves through a fluid increases, will the size of the frictional force that acts on it increase,

decrease or stay the same?
Physics
1 answer:
Alla [95]3 years ago
5 0

Answer:

increase

Explanation:

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The original magnitude of the force on the Q charge was F; what is the magnitude of the force on the Q charge now?
Otrada [13]

Complete Question:

Two small objects each with a net charge of Q (where Q is a positive number) exert a force of magnitude "F" on each other. We

replace one of the objects with another whose net charge is 4Q. The original magnitude of the force on the Q charge was "F"; what is the magnitude of the force on the Q charge now?

Answer:

4 F₀

Explanation:

Assuming that we can treat to both objects as point charges, we can find the force "F" that one charge exerts upon the other applying Coulomb´s law, as follows:

F₀ = K*Q₀² / r₁₂²

If we replace one of the charges by one with a 4Q₀ charge, the new value of F will be as follows:

F₁ = K*Q₀*4Q₀ / r₁₂² =( K*Q₀² / r₁₂²)* 4 = 4* F₀

This value is reasonable, as the electrostatic force is a linear - type one, so it is possible to use the superposition principle (we can get the force exerted by one charge on another without considering the ones due to another charges)

3 0
3 years ago
7 One lb of Refrigerant 134a contained within a piston–cylinder assembly undergoes a process from a state where the temperature
julsineya [31]

Answer:

\Delta S = S_2-S_1 = 0.08835 \frac {BTU} {Lb ^ {\circ} R}

Explanation:

A) In order to solve the table it is necessary to consult tables A11-E and A10E for refrigerant R134-a

In this way we obtain that:

S_1 = S_f = 0.0648 \frac {BTU} {Lb. ^ {\circ} R}

In this way,

S_2 = S_f + x_2 (S_g-S_f) = 0.0902 + 0.5 (0.2161-0.0902)

S_2 = 0.15315 \frac {BTU} {Lb ^ {\circ} R}

In this way the entropy change is,

\Delta S = S_2-S_1 = 0.08835 \frac {BTU} {Lb. ^ {\°} R}

B) Whenever entropy yields a positive result, the process can be carried out adiabatically.

7 0
3 years ago
1. Simplify the following expression<br> 8-6/4-12+3^2
DanielleElmas [232]

Answer:

-5/2

Explanation:

8-6/4-12+3^2

8-6/4-12+9

2/4-12+9

LCM =4

(2-48+36)/4

(-46+36)/4

-10/4

-5/2

5 0
3 years ago
Security is a major concern now that computers play such a large part in healthcare. To address this concern, as well as others
Fed [463]
The correct answer is C. HIPAA

This is the acronym for <span>Health Insurance Portability and Accountability Act. This was done to prevent illegal disclosing of data which was stored in computers and was passed in 1996 when it was signed by the then incumbent president Bill Clinton.</span>
6 0
3 years ago
Read 2 more answers
Two identical spheres with m=3 kg each are rigidly attached to the rotating light rigid structure. The velocity of the spheres i
Dennis_Churaev [7]

Answer:

Angular momentum of the system is 4.8 kg m^2/s

Explanation:

As we know that the angular momentum of the system of masses is given as

L = 2I\omega

here we have

I = m(0.2 + 0.4)^2

I = 3(0.6)^2

now we also know that

\omega = \frac{v}{0.2 + 0.4}

0.6 \omega = 2 m/s

now we have

L = 2(2)(0.6)(2)

L = 4.8 kg m^2/s

3 0
3 years ago
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