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IceJOKER [234]
3 years ago
12

A 1,680 kg satellite is in a circular orbit around Earth with a tangential speed of 6,578 m/s. What is the height of the satelli

te above the surface of the Earth?
Physics
2 answers:
balu736 [363]3 years ago
8 0

Answer:

Recall that Earth’s radius is 6.38 × 106 m and Earth’s mass is 5.97 × 1024 kg.

Explanation:

yaroslaw [1]3 years ago
8 0

Answer:

A- 2.7 on USA Test prep

Explanation:

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Explain the difference between speed and velocity and indicate if these are scalar or vector quantities
Natali5045456 [20]
Speed can never be negative because it does not depend in which direction the car moves whereas, velocity will change if a car turns from due North to East.
Quantities which can be described only by their magnitudes are called scalars and those which are described by both, magnitude and direction are vectors
3 0
3 years ago
What is the most abundant gas in the atmosphere?
Snowcat [4.5K]

Answer: Nitrogen

Explanation: Nitrogen makes up 78% of the atmosphere, Oxygen makes up 21%, and Argon 0.9%.

Water vaper makes up between 1-4%, depending on the region.

Carbon Dioxide makes up only about 0.04%.

8 0
3 years ago
Calculate the energy used by a radio of power 30W in 1 minute.
Alekssandra [29.7K]

Answer:

<u>1.8kJ</u>

Explanation:

Formula :

<u>Energy used = Power x time</u>

<u />

===============================================================

Given :

⇒ Power = 30 W

⇒ Time = 1 minute = 60 seconds

=============================================================

Solving :

⇒ Energy used = 30 W × 60 s

⇒ Energy used = 1,800 J

⇒ Energy used = <u>1.8kJ</u>

5 0
2 years ago
Read 2 more answers
A copper wire 1.0 meter long and with a mass of .0014 kilograms per meter vibrates in two segments when under a tension of 27 Ne
Furkat [3]

Answer:

the frequency of this mode of vibration is 138.87 Hz

Explanation:

Given;

length of the copper wire, L = 1 m

mass per unit length of the copper wire, μ = 0.0014 kg/m

tension on the wire, T = 27 N

number of segments, n = 2

The frequency of this mode of vibration is calculated as;

F_n = \frac{n}{2L} \sqrt{\frac{T}{\mu} } \\\\F_2 = \frac{2}{2\times 1} \sqrt{\frac{27}{0.0014} }\\\\F_2 = 138.87 \ Hz

Therefore, the frequency of this mode of vibration is 138.87 Hz

7 0
3 years ago
Here is a graph of speed vs time. If the object is moving to the east, which BEST describes the speed and velocity of the graph?
san4es73 [151]

Answer: A JUST DID IT ON USA TESTPREP

Explanation:

5 0
3 years ago
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