A girl rolls a basketball across a basketball court. The ball slowly decelerates at a rate of -0.20m/s^2. If the initial velocit
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We are given that a 500 kg object is hanging from a spring. To determine the amount the spring is stretched we will use Hook's law, which states the following:
Where:
Since the object is hanging the only force acting on the spring is the weight of the object. The weight of the object is:
Where:
Plugging in the values we get:
Solving the operations:
Now we solve for "x" from Hook's law by dividing both sides by "k":
Now we plug in the known values:
Solving the operations:
Therefore, the spring is stretched by 5.4 meters.
Answer:
80.17 cm
Explanation:
Taking moments of forces about the center, the total clockwise moments is equal to the total counter clockwise moment:
Force * distance (counter clockwise) = force * distance (clockwise)
0.24 * 9.8 * (50 - 6) = 0.35 * 9.8 * (x - 50)
0.24 * 44 = 3.43x - 171.5
103.5 = 3.43x - 171.5
=> 3.43x = 103.5 + 171.5
3.43x = 275
x = 275/3.43 = 80.17 cm
