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3 years ago

Question 12 (1 point)

Chemistry

2 answers:

Vinvika [58]3 years ago

8 0

Answer:

Option c. Neutral

Explanation:

Only neutral solution gives a green colouration to a pH paper

marishachu [46]3 years ago

5 0

Neutral
There was no change on the red or blue litmus and the ph paper turned green because it had a pH of 7

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shutvik [7]

Answer : The temperature of the chloroform will be, $101.67^oF$

Explanation :

First we have to calculate the mass of chloroform.

$\text{Mass of chloroform}=\text{Density of chloroform}\times \text{Volume of chloroform}=1.4832g/ml\times 74.81ml=110.958g$

conversion used : $(1cm^3=1ml)$

Now we have to calculate the temperature of the chloroform.

Formula used :

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = amount of heat or energy = 1.46 kJ = 1460 J (1 kJ = 1000 J)

$c$ = specific heat capacity = $0.96J/g.K$

m = mass of substance = 110.958 g

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $25^oC=273+25=298K$

Now put all the given values in the above formula, we get:

$1460J=110.958g\times 0.96J/g.K\times (T_{final}-298)K$

$T_{final}=311.706K$

Now we have to convert the temperature from Kelvin to Fahrenheit.

The conversion used for the temperature from Kelvin to Fahrenheit is:

$^oC=\frac{5}{9}\times (^oF-32)$

As we know that, $K=^oC+273$ or, $K-273=^oC$

$K-273=\frac{5}{9}\times (^oF-32)$

$K=\frac{5}{9}\times (^oF-32)+273$ ...........(1)

Now put the value of temperature of Kelvin in (1), we get:

$311.706K=\frac{5}{9}\times (^oF-32)+273$

$T_{final}=101.67^oF$

Therefore, the temperature of the chloroform will be, $101.67^oF$

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tigry1 [53]

Answer:

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$a=\frac{dv}{dt}$

Here, a=acceleartion,

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t=time=12 s

$a=\frac{dv}{dt}$

$a=\frac{36}{12}$

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A car at rest ends accelerates for 12 seconds. After this time the car is going 36 m/s. So acceleration that is a=3 ms⁻².

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