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kirill115 [55]
2 years ago
8

Is the acceleration change or constnt?​

Physics
1 answer:
marin [14]2 years ago
4 0
Change.

Acceleration means going faster
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A large spool in an electrician's workshop has 65 m of insulation-coated wire coiled around it. When the electrician connects a
Art [367]

Answer:

40.34\ \text{m}

Explanation:

L_1 = Length of wire = 65 m

I_1 = Initial current = 1.8 A

I_2 = Final current = 2.9 A

We know

R\propto \dfrac{1}{I}

and

R\propto L

\dfrac{V}{I}\propto L\\\Rightarrow L\propto \dfrac{1}{I}

so

\dfrac{L_2}{L_1}=\dfrac{I_1}{I_2}\\\Rightarrow L_2=\dfrac{I_1}{I_2}L_1\\\Rightarrow L_2=\dfrac{1.8}{2.9}\times 65\\\Rightarrow L_2=40.34\ \text{m}

The length of the wire remaining on the spool is 40.34\ \text{m}.

8 0
3 years ago
an object of mass 20kg is lifted to a 25m building. how much potential energy is stored on a mass?(take g=10m/s²)​
Goshia [24]

Answer:

The answer is 5000 Joules

4 0
3 years ago
g a mass of 1.3 kg is pushed horizontally against a massless spring with a spring constant of 58 n/m until the spring compresses
ExtremeBDS [4]

Answer: 1.102\ J

Explanation:

Given

Mass m=1.3\ kg

Spring constant k=58\ N/m

Compression in the spring x=19.5\ cm\ or\ 0.195\ m

When the mass leaves the spring, the elastic potential energy of spring is being converted into kinetic energy of mass i.e.

\Rightarrow \dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2\\\\\Rightarrow \dfrac{1}{2}\cdot 58\cdot (0.195)^2=\dfrac{1}{2}mv^2\\\\\Rightarrow \dfrac{1}{2}mv^2=1.102\ J

The kinetic energy of the mass is 1.102 J.

5 0
3 years ago
A hockey puck sliding on smooth ice at 4 m/s comes to a 1-m-high hill. Will it make it to the top of the hill?
solniwko [45]

Answer:

No  it will not make to the top of the hill  

Explanation:

From the question we are told that

   The velocity is  v  =  4 \ m/s

    The height of the hill is  h  = 1 \  m

Generally from the law of energy conservation we have that

   The kinetic energy of the pluck at the level position =  The potential energy of the pluck at the maximum height the  pluck can get  to  

So

       \frac{1}{2}  * m * v^2 =  m *  g *  h_{max}

=>    \frac{1}{2}   * v^2 =    g *  h_{max}

=>     h_{max} =   \frac{0.5 * v^2}{g}

=>     h_{max} =  0.8163 \  m

Given that the maximum height which the pluck can get to at this speed given in the question is less than the height of the hill then conclusion will be that the pluck will not make it to the top of the hill

     

3 0
3 years ago
A surface will be an equipotential surface if (there may be more than one correct choice).A. the electric field is zero at all p
aev [14]

Answer:

c. A, C

Explanation:

On equi-potential surface, fields are equal in magnitude at all points . If field is zero at all points , they will be equal so first option is correct.

Field is perpendicular to  equipotential surface at all points.

6 0
3 years ago
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