ΔH = -15.78 KJ when 25.0 g of S₈ reacts.
<h3>What is Balanced Chemical Equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
The given reaction balanced equation is:
1/8 S₈(s) + H₂(g) → H₂S(g) ΔH = -20.22kj
Now,
When 1 mol will react, then ΔH = -20.2 × 8
= -161.6 KJ
When 1 mol of S8 = 8 × 32 g
= 256 g
When 256g of S8 react ΔH = -161.6 KJ
When 1 g reacts, ΔH = 
=- 0.63125 KJ
When 25 g reacts, ΔH = - 0.63125 × 25
= -15.78 KJ
Thus from the above conclusion we can say that ΔH = -15.78 KJ when 25.0 g of S₈ reacts.
Learn more about the Balanced chemical equation here: brainly.com/question/26694427
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Answer:
neutralization reaction
Explanation: Because Neutralization Reactions. ... from a neutralization reaction
Answer: The most likely partial pressures are 98.7MPa for NO₂ and 101.3MPa for N₂O₄
Explanation: To determine the partial pressures of each gas after the increase of pressure, it can be used the equilibrium constant Kp.
For the reaction 2NO₂ ⇄ N₂O₄, the equilibrium constant is:
Kp = 
where:
P(N₂O₄) and P(NO₂) are the partial pressure of each gas.
Calculating constant:
Kp = 
Kp = 0.0104
After the weights, the total pressure increase to 200 MPa. However, at equilibrium, the constant is the same.
P(N₂O₄) + P(NO₂) = 200
P(N₂O₄) = 200 - P(NO₂)
Kp =
0.0104 = ![\frac{200 - P(NO_{2}) }{[P(NO_{2} )]^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B200%20-%20P%28NO_%7B2%7D%29%20%20%7D%7B%5BP%28NO_%7B2%7D%20%29%5D%5E%7B2%7D%7D)
0.0104![[P(NO_{2} )]^{2}](https://tex.z-dn.net/?f=%5BP%28NO_%7B2%7D%20%29%5D%5E%7B2%7D)
+ 
- 200 = 0
Resolving the second degree equation:
= 
= 98.7
Find partial pressure of N₂O₄:
P(N₂O₄) = 200 - P(NO₂)
P(N₂O₄) = 200 - 98.7
P(N₂O₄) = 101.3
The partial pressures are = 98.7 MPa and P(N₂O₄) = 101.3 MPa
Answer:
They are listed below
Explanation:
The 5 things that the periodic table includes are;
1. Name of the element
2. The symbol of the element
3. Atomic number of the element
4. Relative atomic mass
5. Electron configuration
Answer:
iron (III) oxide is a gas
