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allsm [11]
3 years ago
14

Finish A 16 N force is applied to an object and 96 J of work is done. How far was the object moved?

Physics
1 answer:
Lina20 [59]3 years ago
3 0

Answer:

\boxed {\boxed {\sf 6 \ meters}}

Explanation:

Work is the product of force and distance.

W=F*d

We know that 96 Joules of work were done and a 16 Newton force was applied to the object.

  • W= 96 J
  • F= 16 N

Substitute the values into the formula.

96 \  J= 16 \ N * d

First, let's convert the units. This will make cancelling units easier later in the problem. 1 Joule (J) is equal to 1 Newton meter (N*m), so the work of 96 Joules equals 96 Newton meters.

96 \ N*m= 16 \ N * d

Now, solve for distance by isolating the variable, d. It is being multiplied by 16 Newtons and the inverse of multiplication is division. Divide both sides of the equation by 16 N.

\frac {96 \ N*m}{16 \ N}= \frac{16 \ N *d}{16 \ N}

\frac {96 \ N*m}{16 \ N}=d

The units of Newtons cancel.

\frac {96}{16} \ m = d

6 \ m = d

The object moved a distance of <u>6 meters.</u>

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A heat engine with 0.300 mol of a monatomic ideal gas initially fills a 1000 cm3 cylinder at 500 K . The gas goes through the fo
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Complete Question:

A heat engine with 0.300 mol of a monatomic ideal gas initially fills a 1000 cm3 cylinder at 500 K . The gas goes through the following closed cycle: - Isothermal expansion to 5000 cm3. - Isochoric cooling to 400 K . - Isothermal compression to 1000 cm3. - Isochoric heating to 500 K .

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Heat absorbed = Work done due to thermal expansion = 2007.13 J

Thermal efficiency = 402.13/2007.13

Thermal efficiency = 0.2

Thermal efficiency = 0.2 * 100% = 20 %

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