Answer:
of the velocity of a full size plane in the air
Answer:
It decreases.
Explanation:
between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases
Answer:
Explanation:
Venus's atmosphere is very thick, dry and hot whereas Mars's atmosphere is very thin and cold.
Both Venus's and Mars's atmospheres are about 95 percent carbon dioxide.
The surface temperature of Venus is around 890 degrees F, the hottest average temperature in the Solar System. This is due to abundance of greenhouse gasses. The atmosphere of Venus is composed of 97% CO2, 2% N2 and less than 1% of O2, H2O and CH4 (methane). Since CO2 is a major greenhouse gas, the radiation from the Sun is trapped in the atmosphere of Venus producing an extremely high surface temperature.
Mars has an atmospheric composition of 95% CO2, 3% N2, 2% Ar and less than 1% O2.A high noble gas content implies that Mar's atmosphere was much thicker in the past (noble gases do not react with other elements and are heavy enough to stay within the gravitational field of Mars). The climate on Mars is very desert-like due to its thin atmosphere. There is too little mass in the atmosphere to hold in heat so the warmest daytime temperatures are around 50 degrees F, but the nighttime temperatures are -170 degrees F. Other weather features are massive dust storms and occasional CO2 fog in the canyons.
For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length, the electric field intensity 20cm away from the rod is mathematically given as
E1=1.598*10^11v/m
<h3>What is the e
lectric field intensity 20cm away from the
rod along its perpendicular
bisector?</h3>
Generally, the equation for the initial electric field intensity is mathematically given as

Therefore

Hence

E1=B*9*10^{13})/(10*110)*
E1=1.598*10^11v/m
In conclusion, the electric field intensity
E1=1.598*10^11v/m
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