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2 years ago

Which formula can be used to express the law of conservation of momentum, where p=momentum

2 answers:

8 0

<span>pi = pf

</span>hope this helped

you can also check out https://quizlet.com/130467374/momentum-flash-cards/ if you need more help

Mashutka [201]2 years ago

3 0

Explanation :

The momentum of an object is defined as the product of its mass and the velocity with which it is moving.

The law of conservation of momentum states that the total momentum of a system remains conserved when the external force acting on it is equal to zero.

Mathematically, it can be written as :

$p_i=p_f$

where,

$p_i$ and $p_f$ are the initial and the final momentum.

Hence, it is the required solution.

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You perform the Hooke's Law experiment and create a plot of Displacement vs. Force. You add a linear fit and find the following

balandron [24]

Answer: 0.192 N/m

Explanation:

Well, generally when a Hooke's Law experiment is performed the plot is in fact Force vs Displacement, being the Force (in units of Newtons) in the Y-axis and the Displacement (in units of meters) in the X-axis.

In addition, if we add a linear fit the resultant equation will be the Line equation of the form:

$Y=mX+b$

Where $m=\frac{Y_{2}-Y_{1}}{X_{2}-X_{1}}$ is the slope and $b$ is the point where the line intersects the Y-axis.

So, if the equation is:

$Y=0.192X+0.011$

The slope of this line is $0.192 N/m$ which is also the spring constant $k$ .

7 0

3 years ago

An object starts from rest, and accelerates at 2m/s2 for 10s. How far has it gone in that time

blagie [28]

Answer:

100m

Explanation:

$s = ut + \frac{1}{2} a {t}^{2}$

u=0;t=10sec;a=2m/s²

$s = 0(10) + \frac{1}{2}(2 \times {10}^{2} )$

s=10²;100m

7 0

3 years ago

A 10,000 N net force is accelerating a car at a rate of 5.5m/s^2. What is the cars mass

ycow [4]

Answer:

If a net horizontal force of 175 N is applied to a bike whose mass is 43 kg what acceleration is produced? What average net force is ... A 10,000 N net force is accelerating a car at a rate of 5.5 m/s2. What is the car's mass? A boy pedals his ...

Explanation:

6 0

3 years ago

A soft tennis ball is dropped onto a hard floor from a height of 1.50 m and rebounds to a height of 1.10 m. (a) Calculate its ve

Gemiola [76]

Answer:

(a) v = 5.42m/s

(b) vo = 4.64m/s

(d) Δy = 5.11*10^-3m

Explanation:

(a) The velocity of the ball before it hits the floor is given by:

$v=\sqrt{2gh}$ (1)

g: gravitational acceleration = 9.8m/s^2

h: height where the ball falls down = 1.50m

$v=\sqrt{2(9.8m/s^2)(1.50m)}=5.42\frac{m}{s}$

The speed of the ball is 5.42m/s

(b) To calculate the velocity of the ball, after it leaves the floor, you use the information of the maximum height reached by the ball after it leaves the floor.

You use the following formula:

$h_{max}=\frac{v_o^2}{2g}$ (2)