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ivolga24 [154]
3 years ago
7

Write the equation of the line in fully simplified slope-intercept form.​

Mathematics
1 answer:
lina2011 [118]3 years ago
3 0

Answer:

y=-1/2 x-4

Step-by-step explanation:

y=mx+c

c is -4

m is rise/run so -1/2

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What is the sum of the geometric sequence -3, 18, -108, ... if there are 8 terms
creativ13 [48]

Answer:

Step-by-step explanation:

common ratio=18/-3=-108/18=-6, a=-3

sn=a(r^n-1)(r-1)

sn=-3((-6)^n-1)(-6-1)

sn=-3(-6)^8-1)/(-7)

s8=-3(1679615)/(-7)

s8=719836

6 0
2 years ago
Perfect square between 1 and 9
Rasek [7]

Answer:

2

Step-by-step explanation:

4 0
3 years ago
Some help figuring out the answer?? Also explain a little how you got there
ipn [44]

9514 1404 393

Answer:

  x = 10·cos(θ) -4·cot(θ)

Step-by-step explanation:

Apparently, we are to assume that the horizontal lines are parallel to each other.

The relevant trig relations are ...

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

If the junction point in the middle of AB is labeled X, then we have ...

  sin(θ) = 4/BX   ⇒   BX = 4/sin(θ)

  cos(θ) = x/XA   ⇒   XA = x/cos(θ)

Then ...

  BX +XA = AB = 10

Substituting for BX and XA using the above relations, we get

  4/sin(θ) +x/cos(θ) = 10

Solving for x gives ...

  x = (10 -4/sin(θ))·cos(θ)

  x = 10·cos(θ) -4·cot(θ) . . . . . simplify

_____

We used the identity ...

   cot(θ) = cos(θ)/sin(θ)

6 0
3 years ago
Answer. it fast please​
mojhsa [17]

Answer:

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}

Step-by-step explanation:

Given

(\frac{6}{10})^3 * (\frac{5}{9})^2

Required

Solve:

(\frac{6}{10})^3 * (\frac{5}{9})^2

Simplify 6/10

(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{9})^2

Express 9 as 3^2

(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{3^2})^2

Apply law of indices

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{(3^2)^2}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{3^4}

Express as a sing;e fraction

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3*5^2}{5^3*3^4}

Apply law of indices:

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^{3-2}*3^{4-3}}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^1*3^1}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5*3}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}

5 0
2 years ago
1.Which of the following is equivalent to 0.00648
kolbaska11 [484]

Answer:

qd5g

Step-by-step explanation:

8 0
2 years ago
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