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bulgar [2K]
3 years ago
12

The figure shows a water-filled syringe with a 4.0-cm-long needle. What is the gauge pressure of the water at the point P, where

the needle meets the wider chamber of the syringe? The viscosity of water is 1.0×10-3Pa ∙ s.
Physics
1 answer:
mars1129 [50]3 years ago
8 0

Answer:

Pressure at P point is given as

P_p = 1.042 \times 10^5 Pa

Explanation:

As we know by poiseuille's equation of viscous flow of liquid through cylindrical pipe

Q = \frac{\Delta P \pi r^4}{8\eta L}

here we know that

L = 4 cm

\eta = 1 \times 10^{-3} Pa s

r = 1 mm

Q = flow rate

\pi r^2 v = \frac{\Delta P \pi r^4}{8\eta L}

v = \frac{\Delta P r^2}{8 \eta L}

10 = \frac{\Delta P (10^{-3})^2}{8(1 \times 10^[-3})(0.04)}

3.2 \times 10^{-3} = \Delta P (10^{-6})

\Delta P = 3.2 \times 10^3 Pa

now we have

P_p - P_{atm} = 3.2 \times 10^3

P_p = 1.01 \times 10^5 + 3.2 \times 10^3

P_p = 1.042 \times 10^5 Pa

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Answer:

Explanation:

Magnetic field due to moving charge =

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For alpha particle

B_1=\frac{\mu_0}{4\pi} \times \frac{2\times 1.6\times10^{-19}\times 2.8\times 10^5}{(8.25\times 10^{-9})^2}

= 0.1316 x 10⁻³ T

For electron

B_2=\frac{\mu_0}{4\pi} \times \frac{ 1.6\times10^{-19}\times 2.8\times 10^5}{(8.25\times 10^{-9})^2}

= .0658 x 10⁻³ T .

Both these magnetic field will be same in direction because direction of equivalent current is same for both the particles .

Hence

Total magnetic field

= B₁ + B₂ = .1974 x 10⁻³

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8 0
3 years ago
Suppose you have a coffee mug with a circular cross section and vertical sides (uniform radius). What is its inside radius if it
Vlad [161]

Answer:

r = 4.62 cm

Explanation:

Mass of a coffee, m = 370 g

Height of the mug, h = 5.5 cm

We need to find the inside radius of the mug. Density of an object is equal to the mass per unit volume. It can be given by :

d=\dfrac{m}{V}\\\\d=\dfrac{m}{\pi r^2 h}\\\\r=\sqrt{\dfrac{m}{\pi dh}}\\\\r=\sqrt{\dfrac{370\ g}{\pi \times 1\ g/cm^3\times 5.5\ cm}}\\\\r=4.62\ cm

So, the inside radius is 4.62 cm.

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There are no risks when taking medication to treat anxiety.
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Answer:

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Explanation:

5 0
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Read 2 more answers
This homework is meant to be in for today first lesson, please help!!!
Black_prince [1.1K]

The agriculture land needed to grow the willow is 1500000 Hectares

<h3>What is Power?</h3>

Power can be defined as the rate at which work is done by an object. The S.I unit of power is Watt(W).

A coal burning power station burns 6 million tonnes of coal per kg. Coal has a average energy value of 29.25 MJ per year. Wood chip from willow trees has an energy value of 13 MJ per kg. A hectare of agricultural land can produce 9 tonnes of drt willow wood per year.

The coal consumption per year = 29.25 x 1000 x 6000000

                                                    =175500000000 MJ

If this power station burned dry willow wood instead of coal, agriculture land would be needed to grow the willow,

1 hectare of willow will produce 9 x 13x 1000 = 117000 MJ.

The agriculture land needed to grow the willow is

= 175500000000 MJ /  117000 MJ.

= 1500000 Hectares.

Thus, agriculture land needed is  1500000 Hectares.

Learn more about power.

brainly.com/question/15120631

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4 0
2 years ago
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