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REY [17]
3 years ago
14

The plane of a rectangular coil, 7.2 cm by 3.7 cm, is perpendicular to the direction of a uniform magnetic field B. If the coil

has 104 turns and a total resistance of 12.4 Ω, at what rate must the magnitude of B change to induce a current of 0.05 A in the windings of the coil? Answer in units of T/s.
Physics
1 answer:
netineya [11]3 years ago
4 0

Answer:

The rate of change of magnetic field is 2.23 T/s.              

Explanation:

Given that,

Dimension of rectangular coil is 7.2 cm by 3.7 cm.

Number of turns in the coil, N = 104

Resistance of the coil, R = 12.4 ohms

Current, I = 0.05 A

We need to find the rate of change of magnetic field in the coil. The induced emf is given by the rate of change of magnetic flux. So,

\epsilon=-\dfrac{d\phi}{dt}

Ohm's law is :

\epsilon=IR

So,

IR=-\dfrac{d\phi}{dt}\\\\IR=-\dfrac{d(NBA)}{dt}\\\\IR=-NA\dfrac{dB}{dt}\\\\\dfrac{dB}{dt}=\dfrac{IR}{NA}\\\\\dfrac{dB}{dt}=\dfrac{0.05\times 12.4}{104\times 7.2\times 10^{-2}\times 3.7\times 10^{-2}}\\\\\dfrac{dB}{dt}=2.23\ T/s

So, the rate of change of magnetic field is 2.23 T/s.

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The correct option is d

4 0
3 years ago
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maxonik [38]
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