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ipn [44]
3 years ago
5

Ammonia, NH3, can be made by reacting nitrogen and hydrogen and the equation is N2 + 3H2 --> 2NH3 How many moles of NH3 can b

e made if 9 moles of H2 react with enough N2? mol
Chemistry
1 answer:
Mrrafil [7]3 years ago
3 0
9 moles of H2 means you have a total of 18 moles of H2 (9*2). In NH3, the hydrogen comes in sets of 3 (hence H3 at the end) 18/3=6 therefore you need to have made 6 moles of NH3 to satisfy it, since you have enough N2 this can work so you make 6 moles of NH3
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The following charges on individual oil droplets were obtained during an experiment similar to Millikan's. Determine a charge fo
RSB [31]

Answer:

- 1.602 x 10⁻¹⁹coulombs

Explanation:

Charge on individual oil droplet would be multiple of charge on one electron . So we will find out the minimum common factor of given individual charges that is the LCM of all the charges given.

LCM of given charges like 3.204 , 4.806 ,8.01 and 14.42 . We have neglected the power of ten( 10⁻¹⁹)  because it is  already a common factor to all.

The LCM  is 1.602 . So charge on electron is 1.602 x 10⁻¹⁹.

4 0
3 years ago
Calcium chloride is added to the roadways after a snowstorm. Which colligative property is being showcased here?
vlabodo [156]

Answer:

Option (D) freezing point depression

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6 0
3 years ago
What two quantities must be known to calculate the density of a sample of matter? A) mass and volume B) length and mass C) size
Svetradugi [14.3K]

Answer:

A

Explanation:

4 0
2 years ago
Read 2 more answers
As a scuba diver descends under water, the pressure increases. At a total air pressure of 2.71 atm and a temperature of 25.0 C,
Semenov [28]

Answer:

1.32\times 10^{-3} mol/Lis the solubility of nitrogen gas in a diver's blood.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{N_2}=K_H\times p_{liquid}

where,

K_H = Henry's constant = 6.26 \times 10^{-4}mol/L.atm

p_{N_2} = partial pressure of nitrogen

p_{N_2}= P\times \chi_{N_2} (Raoult's law)

=2.71 atm\times 0.78=2.1138 atm

C_{N_2}=6.26 \times 10^{-4}mol/L.atm\times 2.1138 atm

C_{N_2}=1.32\times 10^{-3} mol/L

1.32\times 10^{-3} mol/Lis the solubility of nitrogen gas in a diver's blood.

3 0
3 years ago
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bogdanovich [222]
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3 years ago
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