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PilotLPTM [1.2K]
3 years ago
5

what happens to the radius of the atoms of an element as you go towards the right in a row of the periodic table ?

Chemistry
1 answer:
Olegator [25]3 years ago
7 0

Answer:

It decreases

Explanation:

As one moves from left to right on the periodic table, the radius of atoms reduces due to the nuclear pull.

  • The size of an atom estimated by the atomic radius is taken as half of the internuclear distance between the two covalently bonded atoms of non-metallic elements.
  • Across a period, atomic radius decreases progressively from left to right.
  • This is due to the increasing nuclear charge without attendant increase in the number of electronic shell.
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nlexa [21]
Answer:7 atom of carbon+5atom of hydrogen +3atom of nitrogen +6 atom of oxygen =21

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3 years ago
Calculate the moles of 336 L of carbon dioxide gas (CO2) at STP.
fenix001 [56]

Answer:

14.99 mols of CO2

Explanation:

STP= 273 k , 1 atm , .0821 gas constant

N=PV/RT

N= 1x336/.0821x273

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LUCKY_DIMON [66]

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3 years ago
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8 0
3 years ago
0.378g grams of a compound is made up of 0.273g of Mg and 0.105g nitrogen. Find its empirical formula.
Harrizon [31]

Answer:

The empirical formula of the compound is Mg_3N_2.

Explanation:

Mass of magnesium in compound = 0.273 g

Mass of nitrogen in the compound = 0.105 g

Moles of magnesium =\frac{0.273 g}{24.305 g/mol}=0.0112 mol

Moles of nitrogen = \frac{0.105 g}{14.0067 g/mol}=0.00750 mol

Form empirical formula divides the lowest value of moles of an element present with all the moles of elements present.

Magnesium =\frac{0.0112 mol}{0.00750 mol}=1.5

Nitrogen =\frac{0.00750mol}{0.00750 mol}=1

The empirical formula of a compound:

Mg_{1.5}N_1=Mg_{\frac{15}{10}}N_1=Mg_{15}N_{10}=Mg_3N_2

The empirical formula of the compound is Mg_3N_2.

3 0
3 years ago
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