Answer:7 atom of carbon+5atom of hydrogen +3atom of nitrogen +6 atom of oxygen =21
Answer:
14.99 mols of CO2
Explanation:
STP= 273 k , 1 atm , .0821 gas constant
N=PV/RT
N= 1x336/.0821x273
14.99 mols of CO2
659.6 grams of CO2
I think it's <em>80 . 12</em>
pls tell me if correct
Answer:
The empirical formula of the compound is
.
Explanation:
Mass of magnesium in compound = 0.273 g
Mass of nitrogen in the compound = 0.105 g
Moles of magnesium =
Moles of nitrogen = 
Form empirical formula divides the lowest value of moles of an element present with all the moles of elements present.
Magnesium 
Nitrogen 
The empirical formula of a compound:

The empirical formula of the compound is
.