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4 years ago

What information is required to provide advanced warnings of severe weather conditions?

Physics

2 answers:

Fiesta28 [93]4 years ago

6 0

Answer:

Changes in atmospheric pressure and wind velocities.

Explanation:

Destructive weather patterns like hurricanes, cyclones, and tornadoes are characterized by one thing - a sudden rise or drop in atmospheric pressure. Another significant contribution is the wind velocity. However, the latter is dependent on the former as the wind speed is as a result of a change in pressure.

A sudden lowering of pressure creates a zone of intersection between the two clouds or air zones. This increases the atmospheric pressure. However, the region in the middle of a disaster, say tornado, has a low pressure. The sudden increase in pressure should be a warning sign of a disaster.

OlgaM077 [116]4 years ago

3 0

<span>What type of severe weather, direction the weather, any significant weather that may cause death or property destruction, and what areas will be affected by the severe weather is the information that is required for advance warnings of severe weather conditions. </span>

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3 years ago

a railroad tie weights 920 N and is 2.6 m long. How much force is required to: pick it up off the ground? lift one end and rotat

lukranit [14]

1) The minimum force needed is 920 N

2) The minimum force is 460 N

3) The minimum force is 598 N

Explanation:

We can answer this part by simply looking at the forces involved. In fact, there are two forces acting on the railroad:

Its weight, W, acting downward
The force applied to lift it, F, upward

So the net force on the railroad is

$\sum F = F - W$

where

W = 920 N is the weight of the railroad

In order to lift the railroad, the net force must be upward, so

$\sum F \geq 0$

And therefore

$F\geq W$

which means that the minimum force needed is equal to the weight of the railroad, 920 N.

In this case, we have to use the principle of equilibrium of moments.

In fact, when the railroad rotates uniformly (=constant angular speed) about its end, it means that the moment produced by the weight (acting in one direction) is equal to the moment produced by the force applied (acting in the other direction). Therefore, we can write:

$W \frac{L}{2} = F L$

where

W = 920 N is the weight

L = 2.6 m is the length of the railroad

F is the force applied

We wrote L/2 on the left of the equation because the weight acts at the center of mass of the railroad (located at the midpoint), while on the right it is L because the force F is applied at the end of the railroad.

Solving for F,

$F=\frac{W}{2}=\frac{920}{2}=460 N$

This problem is similar to the previous part, however in this case, the force applied F is applied 0.6 m from the end, pivoting around the opposite end.

This means that the distance between the point of application of the force F and the pivot is

L' = L - 0.6

where

L = 2.6 m

Therefore the equation for the equilibrium of moments becomes

$W\frac{L}{2}=F(L-0.6)$