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-BARSIC- [3]
3 years ago
12

How is carbon dioxide released by animals? *

Chemistry
2 answers:
RUDIKE [14]3 years ago
7 0

Answer:

Exhaled

Explanation:

Anarel [89]3 years ago
7 0

Answer:

Exhale

Explanation:

Just like humans

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Which should you use when creating a budget for your net pay or gross pay
skad [1K]

The net pay should be used for creating your budget.

<h3>What is net pay?</h3>

Your net pay is your take-home pay after the deduction of taxes.

Your total pay before deducting taxes is what is known as gross pay.

Mathematically;

Net pay = Gross pay - taxes.

Thus, if you going to create a budget for yourself, you should only use the pay that is yours, the net pay. Taxes belong to the government.

Budgeting with your gross pay will leave you with deficits by the time taxes are removed from your pay.

More on gross and net pay can be found here: brainly.com/question/14690804

#SPJ1

3 0
2 years ago
A boiler operates at steady state. The entering water is saturated liquid at P = 5 bar and has a flow rate of 10,000 kg/hr. The
stira [4]

Answer:

The rate at which heat is added in the boiler is 8128.610 kilowatts.

Explanation:

A boiler is a device that works at steady state, whose function is pressurizing and heating water. All gravitational electric and magnetic effects can be neglected. From First Law of Thermodynamics the boiler is characterized by the following model:

\dot Q_{in} + \dot H_{in}-\dot H_{out} + \dot K_{in} - \dot K_{out}= 0 (Eq. 1)

Where:

\dot Q_{in} - Heat transfer rate, measured in kilowatts.

\dot H_{in}, \dot H_{out} - Inlet and outlet fluid enthalpy rates, measured in kilowatts.

\dot K_{in}, \dot K_{out} - Inlet and outlet kinetic energy rate, measured in kilowatts.

And by the Principle of Mass Conservation we have that:

\dot m_{in}-\dot m_{out} = 0 (Eq. 2)

Where \dot m_{in} and \dot m_{out} are mass flows at entrance and exit of the boiler, measured in kilograms per second.

Then, we clear the heat transfer rate and expand (Eq. 1) by definitions of enthalpy and kinetic energy, as well as (Eq. 2):

\dot Q_{in} = \dot H_{out}-\dot H_{in}+\dot K_{out}-\dot K_{in}

\dot Q_{in} = \dot m \cdot \left[(h_{out}-h_{in}\right)+\frac{1}{2}\cdot (v_{out}^{2}-v_{in}^{2})\left] (Eq. 3)

Speeds of fluid entering and exiting the boiler (v), measured in meters per second, are found by applying the following formula:

\dot m = \left(\frac{\pi}{4} \right)\cdot \frac{D^{2}\cdot v}{\nu}

v = \frac{4\cdot \dot m\cdot \nu}{\pi\cdot D^{2}} (Eq. 4)

Where:

\nu - Specific volume of fluid, measured in cubic meters per kilogram.

D - Inner diameter of pipe, measured in meters.

Entrance (\dot m = 2.778\,\frac{kg}{s}, \nu_{in} = 0.001093\,\frac{m^{3}}{kg} and D_{in} = 0.08\,m)

v_{in} = \frac{4\cdot \left(2.778\,\frac{kg}{m^{3}} \right)\cdot \left(0.001093\,\frac{m^{3}}{kg} \right)}{\pi\cdot (0.08\,m)^{2}}

v_{in}\approx 0.604\,\frac{m}{s}

Specific enthalpy at given conditions is:

h_{in} = 640.09\,\frac{kJ}{kg} (From Saturated Water tables)

Exit (\dot m = 2.778\,\frac{kg}{s}, \nu_{out} = 0.61731\,\frac{m^{3}}{kg} and D_{out} = 0.30\,m)

v_{out} = \frac{4\cdot \left(2.778\,\frac{kg}{m^{3}} \right)\cdot \left(0.61731\,\frac{m^{3}}{kg} \right)}{\pi\cdot (0.30\,m)^{2}}

v_{out} \approx 24.261\,\frac{m}{s}

Specific enthalpy at given conditions is:

h_{out} = 3272.4\,\frac{kJ}{kg} (From Superheated Steam tables)

If we know that \dot m = 2.778\,\frac{kg}{s}, h_{in} = 640.09\,\frac{kJ}{kg}, h_{out} = 3272.4\,\frac{kJ}{kg}, v_{in}\approx 0.604\,\frac{m}{s}, v_{out} \approx 24.261\,\frac{m}{s}, the heat transfer rate is:

\dot Q = \left(2.778\,\frac{kg}{s} \right)\cdot \left\{ \left(3272.4\,\frac{kJ}{kg}-640.09\,\frac{kJ}{kg}  \right)+\frac{1}{2}\cdot \left[\left(24.261\,\frac{m}{s} \right)^{2}-\left(0.604\,\frac{m}{s} \right)^{2}\right]  \right\}

\dot Q = 8128.610\,kW

The rate at which heat is added in the boiler is 8128.610 kilowatts.

4 0
3 years ago
How easily one thing one thing dissolved into another defined what term? A)elasticity B)solubility C)malleability D)conductivity
stellarik [79]
That is b, solubility 
7 0
4 years ago
Read 2 more answers
The melting points for the compounds li2s, rb2s, and k2s are 900°c, 530°c, and 840°c, respectively. list these three compounds i
Mila [183]

Answer: The order of increasing lattice energy is Li_2S>K_2S>Rb_2S

Explanation: Lattice energy is defined as the energy required to break the intermolecular force that is responsible for the formation of a lattice.

Melting point is defined as the temperature at which solid gets converted into liquid due to the weakening of the bonds in the solid form.

  • Relation between lattice energy and Melting point:

The relationship between these two is direct.

\text{Lattice energy}\propto \text{Melting point}

More the melting point of a compound, more will be its lattice energy.

Order of increasing Lattice energy will be:

Li_2S>K_2S>Rb_2S

7 0
3 years ago
R is the midpoint of FG.<br><br> FR = 26 find RG
vichka [17]

Answer:

52

Explanation:

This is because if R is the midpoint of FRG, FR is half of FRG, so basically all you do it multiply by 2 to get the FRG

7 0
3 years ago
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