What you know:
Vi=0m/s
Vf=143.8m/s
A=-9.8m/s
d=???
Use the equation Vf^2=Vi^2+2A(d)
Rearrange to isolate d: d=Vf^2/2A
d=(143.8)^2/2(-9.8)
d=20678.4/-19.6
d=-1055m
The tank was released from a height of 1055m
A is the only logical answer
We don't have enough information in the picture to answer that question.
The disembodied right hand could just as well grab the wire in the other direction, with the thumb pointing to the right.
Maybe if we knew WHY the hand is holding the wire in this direction, and what other electrical phenomenon may be involved, we might be able to say something about the current in the wire.
(Actually, we don't even know if it's a wire. It might be a soda straw, a coat hanger, or a pool cue.)
Answer:
1 mile
Explanation:
We can use the following equation of motion to solve for this problem:
where v m/s is the final take-off velocity of the airplane, 
initial velocity of the can when it starts from rest, a is the acceleration of the airplanes, which are the same, and 
is the distance traveled before takeoff, which is minimum runway length:
From here we can calculate the distance ratio
Since the 2nd airplane has the same acceleration but twice the velocity
So the minimum runway length is 1 mile
Answer:
energy of electrons in atomic orbitals
Explanation:
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